I have a simple html structure that I need to traverse. For some reason my recursive function returns 'undefined' on any nested nodes, but not for parent nodes. Unfortunately this needs to be native js, no jQuery for this one. Thanks!
HTML:
<div id="container">
<div id="head">
<span id="left"><</span>
<span id="right">></span>
</div>
</div>
Script:
var h = hasId(container, 'head');
var l = hasId(container, 'left');
var r = hasId(container, 'right');
console.log(h + " : " + r + " : " + l);
//[object HTMLDivElement] : undefined : undefined
function hasId(ele, id) {
for (var i = 0; i < ele.childNodes.length; i++) {
var child = ele.childNodes[i];
if(child.id == id) return child;
else hasId(child, id);
}
}
I have a simple html structure that I need to traverse. For some reason my recursive function returns 'undefined' on any nested nodes, but not for parent nodes. Unfortunately this needs to be native js, no jQuery for this one. Thanks!
HTML:
<div id="container">
<div id="head">
<span id="left"><</span>
<span id="right">></span>
</div>
</div>
Script:
var h = hasId(container, 'head');
var l = hasId(container, 'left');
var r = hasId(container, 'right');
console.log(h + " : " + r + " : " + l);
//[object HTMLDivElement] : undefined : undefined
function hasId(ele, id) {
for (var i = 0; i < ele.childNodes.length; i++) {
var child = ele.childNodes[i];
if(child.id == id) return child;
else hasId(child, id);
}
}
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asked May 25, 2012 at 23:08
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- Does this answer your question? undefined returned from function – outis Commented Oct 14, 2021 at 14:48
3 Answers
Reset to default 15You are simply the call to return
on the recursive call. Also, you should test whether its result is defined. If yes, you can return it, or continue looping if not.
var h = hasId(container, 'head');
var l = hasId(container, 'left');
var r = hasId(container, 'right');
console.log(h + " : " + r + " : " + l);
//[object HTMLDivElement] : undefined : undefined
function hasId(ele, id) {
for (var i = 0; i < ele.childNodes.length; i++) {
var child = ele.childNodes[i];
if(child.id == id) return child;
else {
var next = hasId(child, id);
if(next) return next;
};
}
}
The else
clause should return
the value of hasId(child, id)
, but only if that value is itself defined, otherwise it has to continue through the loop.
Without a return
the function will recurse, but not give an answer.
You can fix it like this :
var h = hasId(container, 'head');
var l = hasId(container, 'left');
var r = hasId(container, 'right');
console.log(h + " : " + r + " : " + l);
function hasId(ele, id) {
for (var i = 0; i < ele.childNodes.length; i++) {
var child = ele.childNodes[i];
if(child.id == id || (child = hasId(child, id))){
return child;
}
}
return false;
}