Hi there Dojo developers, I have a drop down form.select, and it has few options, how do set an option to be selected. Say I want to have the third option displayed in the select element. I was looking at the dojo docs and I do not see setSelected() or similar.
Thanks
Hi there Dojo developers, I have a drop down form.select, and it has few options, how do set an option to be selected. Say I want to have the third option displayed in the select element. I was looking at the dojo docs and I do not see setSelected() or similar.
Thanks
Share Improve this question asked Aug 22, 2012 at 16:55 setliosetlio 7262 gold badges14 silver badges32 bronze badges 4-
2
try
selectWidget.set('value', your_option_value)
inside – Sergii Stotskyi Commented Aug 22, 2012 at 16:58 - Thanks serjio, it is attr, but you gave me the right direction, found answer here : stackoverflow./questions/2215979/… – setlio Commented Aug 22, 2012 at 17:26
- it's not important. The main thing is that it was helpful for you, enjoy ;) – Sergii Stotskyi Commented Aug 22, 2012 at 21:16
- Strange just realize that to pull the selected option I have to reselect it from the drop own. Basically it sets the selected option only visually, when I try to get it programmatically it does not return the one visually selected but the first on the list. – setlio Commented Aug 24, 2012 at 0:20
3 Answers
Reset to default 2You need to use displayedValue property in addition to value to set the displayed option. Use something like:
selector.set("displayedValue", "the_text_of_the_option");
or you can search the underlying store of your drop down by using :
selectorStore.fetch({query:{id: value}, onComplete: function (items) {
dojo.forEach(items, function(item){
selector.set("displayedValue", "the_text_of_the_option");
selector.set("value", "the_value_of_the_option");
});
}});
Hope that helps.
I found it, it is selector.attr("value", "the_name_of_the_option");
Thank you, this is true and working. I have tested it. However i discovered my bug: I was creating the options dynamically, and when I set .selected = true as soon as I add it to the selector it changes the sated to the first one being selected.
Or if I apply selector.set("displayedValue", "the_text_of_the_option");
It displays visually the selected one but in fact behind the selected is still the first one does not meter if I change it with the above selector.set. So I solved it by manually creating the selected state. This way when I add it letter id stays in the desired one and changes it accordingly.
Snipped here:
//populate latitude selector
match = false;
optionsArr = [];
for(var i = 0; i < namesLength; i++){
for(var j = 0, len2 = latNames.length; j < len2; j++){
if(fieldNames[i].toLowerCase() == latNames[j]){
for (var a = 0; a < namesLength; a++) {
var option = {};
option.label = fieldNames[i];
option.value = i+"";
if(i==a){
option.selected = true;
}
optionsArr.push(option);
}
match = true;
}
}
}
if(match){
var drop1 = dijit.byId("selectLatitude");
drop1.addOption(optionsArr);
}else{
var drop1 = dijit.byId("selectLatitude");
drop1.addOption(options);//options is an array of options created originally
}