on my login form, i am putting server side validations and if error occurs i want to display those error just below the validated control. Now for this, i am trying to call javascript function to show validation message in php code but not able to call.
<?php
if($_SERVER['REQUEST_METHOD'] == 'POST')
{
if($_POST['txtUsername']=='')
{
//here i want to call javascript function to display message
}
}
?>
<form action="login.php" method="POST">
Username <input type="text" size="30" name="txtUsername" id="user" /><br />
Password <input type="password" size="30" name="txtPassword" id="pass" /><br />
<input type="submit" value="Login" name="loginSubmit"/>
</form>
<script type="text/javascript">
function showMessage(value)
{
document.getElementById(value).innerHTML= value+"can not be empty.";
}
</script>
Please tell me how to display server side validation just below the validated control in form.
on my login form, i am putting server side validations and if error occurs i want to display those error just below the validated control. Now for this, i am trying to call javascript function to show validation message in php code but not able to call.
<?php
if($_SERVER['REQUEST_METHOD'] == 'POST')
{
if($_POST['txtUsername']=='')
{
//here i want to call javascript function to display message
}
}
?>
<form action="login.php" method="POST">
Username <input type="text" size="30" name="txtUsername" id="user" /><br />
Password <input type="password" size="30" name="txtPassword" id="pass" /><br />
<input type="submit" value="Login" name="loginSubmit"/>
</form>
<script type="text/javascript">
function showMessage(value)
{
document.getElementById(value).innerHTML= value+"can not be empty.";
}
</script>
Please tell me how to display server side validation just below the validated control in form.
Share Improve this question asked Feb 20, 2013 at 10:09 Kalpana DixitKalpana Dixit 4493 gold badges7 silver badges20 bronze badges 3- Why don't you validate the inputs from form and then submit the form? – Sudip Commented Feb 20, 2013 at 10:11
- Would it not be useful to actually assign a jQeury script to the submit? The script should then be able to do the validation for you unless I am missing something – Bas Jansen Commented Feb 20, 2013 at 10:11
- Its not working because You are using function before declaring it.Declare script first and then use php. – AZT Commented Oct 27, 2014 at 20:15
4 Answers
Reset to default 3use this
if($_POST['txtUsername']=='')
{
echo '<script> showMessage("txtUsername"); </script>';
}
Something like this
<html>
<head>
<script type="text/javascript">
function showMessage(value)
{
document.getElementById(value).innerHTML= value+"can not be empty.";
}
</script>
</head>
<body>
<?php
if($_SERVER['REQUEST_METHOD'] == 'POST')
{
if($_POST['txtUsername']=='')
{
echo '<script> showMessage("txtUsername"); </script>';
}
}
?>
<form action="login.php" method="POST">
Username <input type="text" size="30" name="txtUsername" id="txtUsername" /><br />
Password <input type="password" size="30" name="txtPassword" id="txtPassword" /><br />
<input type="submit" value="Login" name="loginSubmit"/>
</form>
</body>
</html>
You can put your php code anywhere you like let's say in the body like attribute. You can try the following code:
<body <?php
if($_SERVER['REQUEST_METHOD'] == 'POST')
{
if($_POST['txtUsername']=='')
{
echo "onload = 'showMessage("VALUE")'";
}
}
?> > // end of body start tag
<form action="login.php" method="POST">
Username <input type="text" size="30" name="txtUsername" id="user" /><br />
Password <input type="password" size="30" name="txtPassword" id="pass" /><br />
<input type="submit" value="Login" name="loginSubmit"/>
</form>
</body>
<script type="text/javascript">
function showMessage(value)
{
document.getElementById(value).innerHTML= value+"can not be empty.";
}
</script>
If the validation is successful the php code wont echo anything and the javascript function will not be called. Works for me :). Tell me if this helps.
<?php
if($_SERVER['REQUEST_METHOD'] == 'POST')
{
if($_POST['txtUsername']=='')
{
?>
<script>
//Define the function somewhere in the top or in external js and include it.
callyourfunction();
</script>
<?php
}
}
?> //Its not working