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Enhanced for loop in 2D Array - JavaScript - Stack Overflow

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I created the following 2D array in Javascript

// Create basic linear array
var ImgArray = new Array(4);

// Do the 2D array for each or the linear array slots
for (i=0; i < 4 ; i++) {
    ImgArray[i] = new Array(4)
}

Now i want to iterate through it using 2 ' enhanced for loops'. But am stuck on how to use the loop as there is only ImgArray stated a such. For example;

// Load the images
for(var i in ImgArray) { 
    for( ??? ) {           // How would i do this? What do i state as an array?
          ///...
    }
    document.write("<br>");
}

Any advise well appreciated

I created the following 2D array in Javascript

// Create basic linear array
var ImgArray = new Array(4);

// Do the 2D array for each or the linear array slots
for (i=0; i < 4 ; i++) {
    ImgArray[i] = new Array(4)
}

Now i want to iterate through it using 2 ' enhanced for loops'. But am stuck on how to use the loop as there is only ImgArray stated a such. For example;

// Load the images
for(var i in ImgArray) { 
    for( ??? ) {           // How would i do this? What do i state as an array?
          ///...
    }
    document.write("<br>");
}

Any advise well appreciated

Share Improve this question asked Dec 11, 2010 at 23:23 CarlosCarlos 5,44521 gold badges69 silver badges118 bronze badges 6
  • Also: stop using document.write() - it's pretty evil :-) – Pointy Commented Dec 11, 2010 at 23:44
  • document.write is OK, "enhanced for loops" (for...in array) is not. – Free Consulting Commented Dec 11, 2010 at 23:46
  • 1 @Pointy: There's nothing wrong with document.write, used appropriately. – Tim Down Commented Dec 11, 2010 at 23:56
  • 1 If you use var a = new Array(4), remember that it will create an array of length 4 but that it does not contain any elements, a[1] will return undefined, but a.length will return 4. – Felix Kling Commented Dec 12, 2010 at 0:03
  • 2 @Tim Down, @Carlos - document.write() is one of those things that does what it does, and it's not inherently "bad", but it's a way of doing things that really calls for a new approach. The better way to do things is via DOM manipulation after the document has loaded. @Tim the key there is used appropriately. – Pointy Commented Dec 12, 2010 at 5:03
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3 Answers 3

Reset to default 16

Assuming the array you've created, the loop looks like this:

var i, j, entry, ImgArray;

// Create the array
ImgArray = new Array(4);
for (i=0; i < 4 ; i++) {
    ImgArray[i] = new Array(4);
}

// Loop through both dimensions
for (i = 0; i < ImgArray.length; ++i) {
    entry = ImgArray[i];
    for (j = 0; j < entry.length; ++j) {
        // Do something with entry[j]
    }
}

This is because there are no two-dimensional arrays in JavaScript. (In fact, even arrays aren't really arrays, but let's not go there.) There are "arrays", and an array entry can be another array, but one array entry might be longer or shorter than others. So you retrieve that array and loop through its length, which may be different than others in the same "dimension".

Note that I didn't use for..in above. Don't use for..in to loop through arrays unless you really know what you're doing; details here. (If you do really know what you're doing and take adequate precautions, it's fine, but your quoted code isn't taking the necessary precautions.) for..in does not iterate the indexes of an array, it enumerates the property names of an object.

Off-topic #1: In JavaScript, the convention (which you're free to ignore) is to only use initial caps (ImgArray) for constructor functions.

Off-topic #2: You might look at using array literals ([entry, entry, entry]) rather than new Array(...), but it depends on what you're doing.

Off-topic #3: It's a very bad idea to rely on semicolon insertion (as with your ImgArray[i] = new Array(4) line). Make sure to put in the semicolons where they're needed, or you'll find that you can't minify your scripts properly and/or that you'll fight odd bugs that waste your time. :-)

That's not an "enhanced for loop". You should not be iterating through Array instances that way anyway, at least not when you're treating them semantically as integer-indexed arrays.

Use your original

for (var i = 0; i < 4; ++i)

approach (and don't forget var). Also don't bother with

var ImgArray = new Array(4);

Just write

var ImgArray = [];

you just have to do a for loop for both as such

for (var i in array){
   for(var j in array[i]){//do stuff here}
}
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