我正在尝试查找b/w 2列表的唯一值，但是这种逻辑似乎不起作用
I am trying to find unique values b/w 2 lists but this logic doesn't seems to work
x = [1,2,3,4] f = [1,11,22,33,44,3,4] for element in f: if element in x: f.remove(element) print f所需的输出
[11, 22, 33, 44]实际输出
[11, 22, 33, 44, 4]仅从两个列表python中获取唯一元素
同样在这里问 解决方案:
same ask here solution:
x = [1,2,3,4] f = [1,11,22,33,44,3,4] res = list(set(x+f)) print(res) [1, 2, 3, 4, 33, 11, 44, 22]如您所见，其添加的1,2,3,4未输出，我需要
as you can see its adding 1,2,3,4 not output I need
推荐答案在关闭和重新打开所有麻烦之后，我觉得有人应该真正回答这个问题.
After all the hassle with closing and re-opening I feel someone ought to actually answer the question.
有多种方法可以达到预期效果:
There are different ways to achieve the desired result:
列表理解:[i for i in f if i not in x].效率可能较低，但可以保留顺序.功劳归 Chris_Rands (上面的评论).
List comprehensions: [i for i in f if i not in x]. Maybe less efficient but preserves order. Credit goes to Chris_Rands (comment above).
设置操作:set(f) - set(x).对于较大的列表，可能更有效，但不会保留顺序. Gredit转到 mpf82 .正如 asongtoruin 指出的那样，这也会删除f中的重复项.
Set operations: set(f) - set(x). Likely more efficient for larger lists but does not preserve order. Gredit goes to mpf82. This also removes duplicates in f, as pointed out by asongtoruin.