嗨 任何人都可以帮助我在c＃ 中使用正则表达式来获得解决方案基本上我必须在 * p0x0Y 之前添加一些文字模式。在这个模式中，p，x，y将是固定值，0可以被任何数字替换。 i必须编辑
string str = ?? l8c1E？ * p0x0Y在此字符串中* p0x0Y可以是* p1x1Y或* p2x2Y。 和编辑后的输出应该是* p0x0Y格式
string output = 18c1EXXX * p0x0Y提前致谢。
解决方案尝试： string str = l8c1E * p0x0Y; string output = Regex.Replace（str， @ （\ * p\dx \ dY）， @ XXX
1）;
嗨OriginalGriff，你的解决方案对我有用，现在我想再问一件事......我必须在下面的文字中将左侧字符串替换为右侧字符串..在本文中左箭头标志是一个符号我无法复制粘贴，所以我用文字写了它，它只是一个符号。所以请给我正则表达式代码来替换它。左箭头标志* p0x0Y - >左箭头标志xxx左箭头标志 * p0x0Y我清楚我的要求，原件？ 如果不知道确切的字符，我不能确定，但是...点字符匹配任何东西，所以它可能是你想要的是：
string output = Regex.Replace（str， @ （。）（\ * p\dx \ dY）， @1XXX
Hi Can anybody help me to get the solution using regular expression in c# basically i have to add some text before *p0x0Y pattern . In this pattern p,x,y will be fix value and 0 can be replace by any number . i have to edit a
string str= "l8c1E*p0x0Y"In this string *p0x0Y can be *p1x1Y or *p2x2Y . and after editing output should be according *p0x0Y format
string output = "18c1EXXX*p0x0Y"Thanks in advance .
解决方案 Try: string str = "l8c1E*p0x0Y"; string output = Regex.Replace(str, @"(\*p\dx\dY)", @"XXX1");"Hi OriginalGriff , Your solution worked for me , now i want to ask one more thing ... i have to replace left side string into right side string in below text .. In this text "left arrow sign" is one symbol which i could not copy paste so i wrote it in text ,its just one symbol. So please give me regular expression code to replace it . "left arrow sign"*p0x0Y --> "left arrow sign"xxx "left arrow sign"*p0x0Y Am i clear about my requirement , Original ?" Without knowing the exact character, I can't be sure, but...the dot character matches anything, so it might be that what you want is:
string output = Regex.Replace(str, @"(.)(\*p\dx\dY)", @"1XXX