I want to extract the plete path i.e the path followed by the host name of a URL in javascript.

var url = '.php/fghfgh?id=1'

Here i want to extract /file.php/fghfgh?id=1

How can this achieve only using regular expression not by "document.createElement('a')" methode ?

I need the answer in regular expression ,

I want to extract the plete path i.e the path followed by the host name of a URL in javascript.

var url = 'https://domain.us/file.php/fghfgh?id=1'

Here i want to extract /file.php/fghfgh?id=1

How can this achieve only using regular expression not by "document.createElement('a')" methode ?

I need the answer in regular expression ,

• javascript
• regex

• Does the url always end with .us ?? Maybe you could just simply use the string.split(".us") --- This returns an array where array[1] holds the url part you want. – w00 Commented Mar 13, 2012 at 9:02
• what is the "document.createElement('a')" method?, I have never heard of it before. – Ali Khalid Commented Mar 13, 2012 at 9:03
• Possible duplicate of Regular expression to remove hostname and port from URL? – stema Commented Mar 13, 2012 at 9:34
• the above one is just an example .I want to extract the string (include pathname + searchname) after the hostname of any url .Need answer in regular expression – Achu Commented Mar 13, 2012 at 9:45

4 Answers 4

If you are accessing the location object, you could do

var path = location.href.replace(location.protocol+"//"+location.hostname,"")

or

var path = location.pathname+location.search

If you have # you may need to add it too as pointed out by just_mad:

var path = location.pathname+location.search+location.hash

^[^#]*?://.*?(/.*)$

Credit goes to strager:

Regular expression to remove hostname and port from URL?

How about using something tried and true: http://blog.stevenlevithan./archives/parseuri

There's even a demo: http://stevenlevithan./demo/parseuri/js/

and here is a much more specific regex for your question;

https?://[-A-Z0-9.]+(/[-A-Z0-9+&@#/%=~_|!:,.;?]*)?