I have this forumula in a Excel sheet :
=IF(B$3=0,B$14*B$2*B$6,(1-((1+B$3))^B$6)/LN(1/(1+B$3))*B12*B$2)
where cells:
B2 = 40000
B3 = 1.0%
B6 = 30
B12 = 10.0%
B14 = 20.0%
The excel produces the following result: 139,834
I started looking at the 'else' part seeing as B3 not equal to 1, however I having issues with my calculations in JavaScript. Below is what I got (code is inside a function):
var B2 = 40000;
var B3 = 1/100;
var B6 = 30;
var B12 = 10/100;
var B14 = 20/100;
var calc = Math.pow ((1-(1+B3)),B6) / Math.log ( (1 / (1+B3)) * B12 * B2);
return ( calc );
What I'm getting back is 1.2071318349401829e-61
Anyone know where I'm going wrong or how I would go about getting the correct result in JavaScript?
Any help appreciated.
I have this forumula in a Excel sheet :
=IF(B$3=0,B$14*B$2*B$6,(1-((1+B$3))^B$6)/LN(1/(1+B$3))*B12*B$2)
where cells:
B2 = 40000
B3 = 1.0%
B6 = 30
B12 = 10.0%
B14 = 20.0%
The excel produces the following result: 139,834
I started looking at the 'else' part seeing as B3 not equal to 1, however I having issues with my calculations in JavaScript. Below is what I got (code is inside a function):
var B2 = 40000;
var B3 = 1/100;
var B6 = 30;
var B12 = 10/100;
var B14 = 20/100;
var calc = Math.pow ((1-(1+B3)),B6) / Math.log ( (1 / (1+B3)) * B12 * B2);
return ( calc );
What I'm getting back is 1.2071318349401829e-61
Anyone know where I'm going wrong or how I would go about getting the correct result in JavaScript?
Any help appreciated.
Share Improve this question edited Jul 22, 2011 at 14:29 Sukh asked Jul 22, 2011 at 14:20 SukhSukh 252 silver badges5 bronze badges 2- in your js, B14 is worth 10% (VS 20% in Excel), is it a typo ? – JMax Commented Jul 22, 2011 at 14:22
- Yes sorry that is a type it should be 20% - var B14 = 20/100; – Sukh Commented Jul 22, 2011 at 14:28
1 Answer
Reset to default 4In excel you have
1-((1+B$3))^B$6
which is the same as
1-(1+B$3)^B$6
in javascript you have
Math.pow ((1-(1+B3)),B6)
which is different