I want to return information about a blog. It could be, author name, title, date, country whatever just to test.

<?php
    $post_id = get_the_ID();
    while ($post_id != 0) 
        {
            $queried_post = get_post($post_id);
            $author_id = $queried_post->post_author;
            echo get_the_author_meta('display_name',$author_id);
            $post_id++;
        }
?>

In the following code, I'm trying to get all the author's name between post_id 20 to 25. When the code is run, it only displays:

The author is: 
The author is: 
The author is: 
The author is: 
The author is: 
The author is:

Can you tell me how i would fix it so that it would return any kind of information about the blog (in this case, the name of the author).

THE UPDATED CODE DOESN'T DISPLAY ANYTHING.

I want to return information about a blog. It could be, author name, title, date, country whatever just to test.

<?php
    $post_id = get_the_ID();
    while ($post_id != 0) 
        {
            $queried_post = get_post($post_id);
            $author_id = $queried_post->post_author;
            echo get_the_author_meta('display_name',$author_id);
            $post_id++;
        }
?>

In the following code, I'm trying to get all the author's name between post_id 20 to 25. When the code is run, it only displays:

The author is: 
The author is: 
The author is: 
The author is: 
The author is: 
The author is:

Can you tell me how i would fix it so that it would return any kind of information about the blog (in this case, the name of the author).

THE UPDATED CODE DOESN'T DISPLAY ANYTHING.

• php
• functions
• loop

• The author is: <?php the_author_meta( 'display_name', $author_id ); ?> - do you have something like that in your code? Or maybe echo 'The author is: ' . get_the_author_meta( 'display_name', $author_id ); ? And if you're in the standard Loop (while ( have_posts() ) ...), you wouldn't need to specify the second parameter there (the $author_id - i.e. the user ID). – Sally CJ Commented May 9, 2019 at 20:12
• @SallyCJ how would i return $post_id using that code? $author_id = $queried_post->post_id; Did that but nothing. – – J patel Commented May 10, 2019 at 17:21
• I'm sure you already have the answer by now, @Jpatel. :) – Sally CJ Commented May 10, 2019 at 19:15

2 Answers 2

You need to re-arrange your code.

<?php 
        $post_id = 20;

        while($post_id <= 25) {
            $queried_post = get_post($post_id); 

            $author_id = $queried_post->post_author;
            echo get_the_author_meta('display_name', $author_id);


            $post_id++;
        } 
?>

Within while loop above you have $queried_post which is an object of class WP_Post. Member Variables of WP_Post can be used to display data about each post.

I hope this may help.

UPDATE

what if i want to the loop to apply to all of the post that there are on the site. What would be the changes i would need to make in order for me to apply to all the posts?

In that case you may code like that using get_posts() which returns an array of objects

<?php 
        $arg = array( 'numberposts' => -1 );  // get all posts

        $queried_posts = get_posts( $arg);

        // Now loop through $queried_posts
        foreach( $queried_posts as $queried_post ) {

            $author_id = $queried_post->post_author;
            echo get_the_author_meta('display_name', $author_id);

        } 
    ?>

You will want to get the author name inside the loop. Once your inside the loop you will be dealing with one post at a time, then you can access any post info you need. https://codex.wordpress/Class_Reference/WP_Post

**Qaisar has it right for your while loop. Inside the loop you have to get the post. $queried_post = get_post($post_id); then you can get the author...

UPDATED AGAIN

<?php

    $args = [
    'post__in' => range( 20, 25 ), //**get post in your range**
    ];
    $queried_posts= get_posts( $args ); // **now you have the post you want**

    foreach( $queried_posts as $queried_post ) {  // **loop through**
        $author_id = $queried_post->post_author;
        echo get_the_author_meta('display_name', $author_id) .'</br>';
    }
?>