最新消息:雨落星辰是一个专注网站SEO优化、网站SEO诊断、搜索引擎研究、网络营销推广、网站策划运营及站长类的自媒体原创博客

JavaScript Object - Find one property -> change to true and change all others to false - Stack Overflow

programmeradmin4浏览0评论

Is there any way I can shorten this bit of code and logic? This code is currently very long. Maybe there is something I can do with map, hash or whatever?

As you can see, I have an object with 7 properties. I want an easy way of changing one target property to true and all 6 others to false.

 var object = {
        a: false,
        b: false,
        c: false,
        d: false,
        e: false,
        f: false,
        g: false
    }

    target = "b";

    switch(target) {
        case a:
            object.a = true;
            object.b = false;
            object.c = false;
            object.d = false;
            object.e = false;
            object.f = false;
            object.g = false;
            break;
        case b:
            object.a = false;
            object.b = true;
            object.c = false;
            object.d = false;
            object.e = false;
            object.f = false;
            object.g = false;
            break;
        case c:
            object.a = false;
            object.b = false;
            object.c = true;
            object.d = false;
            object.e = false;
            object.f = false;
            object.g = false;
            break
        case d:
            object.a = false;
            object.b = false;
            object.c = false;
            object.d = true;
            object.e = false;
            object.f = false;
            object.g = false;
            break;
        case e:
            object.a = false;
            object.b = false;
            object.c = false;
            object.d = false;
            object.e = true;
            object.f = false;
            object.g = false;
            break
        case f:
            object.a = false;
            object.b = false;
            object.c = false;
            object.d = false;
            object.e = false;
            object.f = true;
            object.g = false;
            break;
        case g:
            object.a = false;
            object.b = false;
            object.c = false;
            object.c = false;
            object.d = false;
            object.e = false;
            object.f = false;
            object.g = true;
            break;
    }

How can I set the property given in target to true, while setting the other 6 to false?

Is there any way I can shorten this bit of code and logic? This code is currently very long. Maybe there is something I can do with map, hash or whatever?

As you can see, I have an object with 7 properties. I want an easy way of changing one target property to true and all 6 others to false.

 var object = {
        a: false,
        b: false,
        c: false,
        d: false,
        e: false,
        f: false,
        g: false
    }

    target = "b";

    switch(target) {
        case a:
            object.a = true;
            object.b = false;
            object.c = false;
            object.d = false;
            object.e = false;
            object.f = false;
            object.g = false;
            break;
        case b:
            object.a = false;
            object.b = true;
            object.c = false;
            object.d = false;
            object.e = false;
            object.f = false;
            object.g = false;
            break;
        case c:
            object.a = false;
            object.b = false;
            object.c = true;
            object.d = false;
            object.e = false;
            object.f = false;
            object.g = false;
            break
        case d:
            object.a = false;
            object.b = false;
            object.c = false;
            object.d = true;
            object.e = false;
            object.f = false;
            object.g = false;
            break;
        case e:
            object.a = false;
            object.b = false;
            object.c = false;
            object.d = false;
            object.e = true;
            object.f = false;
            object.g = false;
            break
        case f:
            object.a = false;
            object.b = false;
            object.c = false;
            object.d = false;
            object.e = false;
            object.f = true;
            object.g = false;
            break;
        case g:
            object.a = false;
            object.b = false;
            object.c = false;
            object.c = false;
            object.d = false;
            object.e = false;
            object.f = false;
            object.g = true;
            break;
    }

How can I set the property given in target to true, while setting the other 6 to false?

Share Improve this question edited Aug 21, 2019 at 16:22 Luke B 2,1463 gold badges19 silver badges28 bronze badges asked Aug 21, 2019 at 15:30 David CottoDavid Cotto 437 bronze badges 1
  • 4 What's the question? – Pointy Commented Aug 21, 2019 at 15:30
Add a ment  | 

4 Answers 4

Reset to default 4

A simple loop over the keys and set each one to false/true if it matches

var myObject = {
  a: false,
  b: false,
  c: false
}


function updateState (active) {
  Object.keys(myObject).forEach( function (key) {
    myObject[key] = key === active
  })
}


/*
const updateState = active => 
  Object.keys(myObject).forEach( key =>
    myObject[key] = key === active
  )
*/

console.log(JSON.stringify(myObject))
updateState('b')
console.log(JSON.stringify(myObject))
updateState('c')
console.log(JSON.stringify(myObject))

Simply set all values to false, then set the value you want to true:

var object = {
  a: false,
  b: false,
  c: false,
  d: false,
  e: false,
  f: false,
  g: false
}

target = "b";
for (var prop in object) {
  object[prop] = false;
}

object[target] = true;

I'm a bit confused. Your object has all properties already set to false. Is the assumption that this object will not always have all properties set to false? If so this would be my approach.

var object = {
    a: false,
    b: false,
    c: false,
    d: false,
    e: false,
    f: false,
    g: false
}

target = "b";

object = _.mapValues(object, () => false);

object[target] = true;
var object = {
    a: false,
    b: false,
    c: false,
    d: false,
    e: false,
    f: false,
    g: false
}
target = "b";
Object.keys(object).forEach(key => {
  object[key] = false
})
object[target] = true
发布评论

评论列表(0)

  1. 暂无评论