最新消息:雨落星辰是一个专注网站SEO优化、网站SEO诊断、搜索引擎研究、网络营销推广、网站策划运营及站长类的自媒体原创博客

JSON.parse() not working in javascript in pentaho - Stack Overflow

programmeradmin2浏览0评论

I am trying to form an array from a string using Modified Java Script Value step. Here is my code to parse a string and to form a JSON object.

var info = {};
var keywords = 'Adjust course (C-6),Identify underlying factors (C-4),Isolate teacher actions (C-3_)';
if(keywords != null && keywords != ''){
keywords = keywords.replace(/,/g,'","');
keywords = '["'+keywords+'"]';
info.keywords = JSON.parse(keywords);
}

Here in JSON.parse() it throws an error SyntaxError: Missing ma in array literal.

Can anyone please help me parse the array and store in json object.

Thanks in advance!

I am trying to form an array from a string using Modified Java Script Value step. Here is my code to parse a string and to form a JSON object.

var info = {};
var keywords = 'Adjust course (C-6),Identify underlying factors (C-4),Isolate teacher actions (C-3_)';
if(keywords != null && keywords != ''){
keywords = keywords.replace(/,/g,'","');
keywords = '["'+keywords+'"]';
info.keywords = JSON.parse(keywords);
}

Here in JSON.parse() it throws an error SyntaxError: Missing ma in array literal.

Can anyone please help me parse the array and store in json object.

Thanks in advance!

Share Improve this question asked Apr 12, 2016 at 6:38 ArunrajArunraj 5685 silver badges22 bronze badges 5
  • I executed your code in the Chrome dev console and it works fine. Also in JavaScript you can pact the if clause like so: if(keywords){...} – fikkatra Commented Apr 12, 2016 at 6:45
  • 1 You also can use eval function, but be careful! – savelichalex Commented Apr 12, 2016 at 6:46
  • @Arunraj Please show what should you want to get after this code, I think that have more correct solution for you – savelichalex Commented Apr 12, 2016 at 6:50
  • Can you console.log(keywords) before parsing in your environment and tell what is it? – Rajaprabhu Aravindasamy Commented Apr 12, 2016 at 7:01
  • java.lang.System.out.println(keywords); – simar Commented Apr 12, 2016 at 13:20
Add a ment  | 

3 Answers 3

Reset to default 2

Try this one

if(keywords){
  keywords = keywords.split(',');
  info.keywords = keywords;
}

Try this:

function kwInfo(text)
{
    return JSON.parse('["' + (text || '').split(',').join('","') + '"]');
}

var text = 'Adjust course (C-6),Identify underlying factors (C-4),Isolate teacher actions (C-3_)';
var info = {keywords:kwInfo(text)};

console.log(info);

Run kettle in console mode SpoonConsole.bat

var info = {};
var keywords = 'Adjust course (C-6),Identify underlying factors(C-4),Isolate 
teacher actions (C-3_)';

java.lang.System.out.println("Original : " + keywords);

if(keywords != null && keywords != ''){
   keywords = keywords.replace(/,/g,'","');
   java.lang.System.out.println("Regexp applied : " + keywords);
   keywords = '["'+keywords+'"]';
   java.lang.System.out.println(keywords);
   info.keywords = JSON.parse(keywords);
}

Look into console and trace the error in logic

This is only way I found to trace JavaScript step

发布评论

评论列表(0)

  1. 暂无评论