I want to find Latitude, for example

Point A = (18.5204303,73.8567437)
Point B = (x,73.8567437)
Distance =20KM(Kilometers)

I need to find the latitude(x) of Point B, that is 20 KM from point A.Longitude should be same. Help me Thanks in advance

I want to find Latitude, for example

Point A = (18.5204303,73.8567437)
Point B = (x,73.8567437)
Distance =20KM(Kilometers)

I need to find the latitude(x) of Point B, that is 20 KM from point A.Longitude should be same. Help me Thanks in advance

• javascript
• dictionary
• geolocation
• geospatial

• 1 Don't you need an angle as well? Otherwise there is an infinite number of B = (x, y) points matching your criteria - on a circle with 20km radius and centre in A... – Tomasz Nurkiewicz Commented Jan 15, 2012 at 9:50
• Yes,i need Angular radius, But i don't know how to find it. – Nishu Commented Jan 15, 2012 at 9:53
• 2 so you have a single equation with two unknowns - math is against you ;-). You need to know both: radius and angle to be able to find exactly one B. – Tomasz Nurkiewicz Commented Jan 15, 2012 at 9:56
• I checked this link janmatuschek.de/LatitudeLongitudeBoundingCoordinates (section 3.1) sort out with some formula,But it is not matching with the circle drawn at 20km – Nishu Commented Jan 15, 2012 at 10:00
• i apologize, here longitude will be fixed that is in Point A = (18.5204303,73.8567437) Point B = (x,73.8567437) Distance =20KM(Kilometers) – Nishu Commented Jan 15, 2012 at 10:03

3 Answers 3

i found answer for my question

var lat1 = 18.5204303;
    var lon1 = 73.8567437;
    var d = 20;   //Distance travelled
    var R = 6371;
    var brng = 0;
    var LatMax;
    brng = toRad(brng); 
    var lat1 = toRad(lat1), lon1 = toRad(lon1);
    var lat2 = Math.asin( Math.sin(lat1)*Math.cos(d/R) + 
                      Math.cos(lat1)*Math.sin(d/R)*Math.cos(brng) );

    var lon2 = lon1 + Math.atan2(Math.sin(brng)*Math.sin(d/R)*Math.cos(lat1), 
                             Math.cos(d/R)-Math.sin(lat1)*Math.sin(lat2));
        lon2 = (lon2+3*Math.PI) % (2*Math.PI) - Math.PI;  
    lat2= toDeg(lat2);
    lon2= toDeg(lon2);
    alert(lat2);
    alert(lon2);

function toRad(Value) {
    /** Converts numeric degrees to radians */
    return Value * Math.PI / 180;
}
 function toDeg(Value) {
   return Value * 180 / Math.PI;
}

Thank you all

I'm not sure if this should be an answer or a ment. But since I can't write ments yet I'll write an answer.

This page is a great source for doing distance calculations. In this case you are probably looking for code to calculate the new position when traveling along a rhumb line from a given position. Quote from linked page:

To find the lat/lon of a point on true course tc, distance d from (lat1,lon1) along a rhumbline (initial point cannot be a pole!):

lat= lat1+d*cos(tc)
IF (abs(lat) > pi/2) "d too large. You can't go this far along this rhumb line!"
IF (abs(lat-lat1) < sqrt(TOL))
{
    q=cos(lat1)
}
ELSE 
{
    dphi=log(tan(lat/2+pi/4)/tan(lat1/2+pi/4))
    q= (lat-lat1)/dphi
}
dlon=-d*sin(tc)/q
lon=mod(lon1+dlon+pi,2*pi)-pi

The link is still useful but you will have to use some algebra to solve for a known longitude and unknown course. Since you are quite far north great circle distances may be more useful than rhumb lines. But I guess that depends on the problem.

I am not an expert in this. But i used to calculate the distance between two points using the formulae by movable-type.

Please check the site. it ll give you some hint. I think this destination and rhumblines formulae are similar to your requirement. Have a look