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Firefox Javascript: Why does .all not work? - Stack Overflow

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In IE, I can go like:

var x = document.getElementById("header");

alert(x.all[0].tagName);

If I try that in Firefox, I get the error "all is undefined".

What is the Firefox equivalent of IE's .all property?

In IE, I can go like:

var x = document.getElementById("header");

alert(x.all[0].tagName);

If I try that in Firefox, I get the error "all is undefined".

What is the Firefox equivalent of IE's .all property?

Share Improve this question edited Jul 30, 2012 at 18:28 Rustam 1,9332 gold badges16 silver badges35 bronze badges asked Apr 14, 2011 at 16:12 oscilatingcretinoscilatingcretin 11k41 gold badges128 silver badges214 bronze badges
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2 Answers 2

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.all is a Microsoft-specific extension to the DOM, and is not supported by any other browsers (except Opera, I believe, who simulate it in order to improve patibility with sites written for IE).

You can use things like x.children and x.childNodes, or x.getElementById() and x.getElementsByTagName() to reference elements below the current one in the tree, depending on your usage. I suspect in this case x.children is what you're after.

all would be the name of an array. It is not a native javascript keyword.

You may want to look at childNodes instead.

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