I have an array with timeout id's. What is the most elegant way to clear all of them at once? Is there a more efficient style than this?

waitHandler[1] = setTimeout('doSomethingA()', 2000);
waitHandler[2] = setTimeout('doSomethingB()', 2000);
...

for (var i=1; i < waitHandler.length; i++) {
    clearTimeout[i];
}

I have an array with timeout id's. What is the most elegant way to clear all of them at once? Is there a more efficient style than this?

waitHandler[1] = setTimeout('doSomethingA()', 2000);
waitHandler[2] = setTimeout('doSomethingB()', 2000);
...

for (var i=1; i < waitHandler.length; i++) {
    clearTimeout[i];
}

• javascript
• cleartimeout

• Don't write code in strings. var t = 2000; var ids = [setTimeout(doSomethingA, t), ...]; – 1983 Commented Nov 18, 2014 at 10:33
• Okay, but what if I need to consign params? – Robbit Commented Nov 18, 2014 at 11:42
• Then use anonymous functions: setTimeout(function(){doSomethingA(param)}) – Scimonster Commented Nov 18, 2014 at 11:44
• Ah, is this more performant or just a better coding style? – Robbit Commented Nov 18, 2014 at 12:58

2 Answers 2

waitHandler.forEach(clearTimeout);

I think what you mean to do is this:

for (var i=1; i < waitHandler.length; i++) {
    clearTimeout(waitHandler[i]);
}

Your old syntax wouldn't work.

And this is the only way to do it without plugins.