Given that:

var pattern = "{0}";

Why does this not work:

pattern.replace(/\{0\}/g, "$0.00");

and yet:

pattern.replace("{0}", "$0.00");

the first results in: "{0}.00" the second results in "$0.00"

meanwhile the following does work as expected (producing "$1.00"):

pattern.replace(/\{0\}/g, "$1.00");

Any tips or advice would be really appreciated.

Given that:

var pattern = "{0}";

Why does this not work:

pattern.replace(/\{0\}/g, "$0.00");

and yet:

pattern.replace("{0}", "$0.00");

the first results in: "{0}.00" the second results in "$0.00"

meanwhile the following does work as expected (producing "$1.00"):

pattern.replace(/\{0\}/g, "$1.00");

Any tips or advice would be really appreciated.

• javascript
• regex
• replace

• 1 don't use { use ( – progrenhard Commented Sep 11, 2013 at 20:20
• Actually both examples work fine in Chrome. Which browser are you testing with? – tmh Commented Sep 11, 2013 at 20:23

1 Answer 1

In a replacement string with regex, $0 (and $&) represent the entire match. $1 represents the first subpattern, and so on.

The appropriate workaround is to use $$, as this will be replaced with a literal $.

pattern.replace(/\{0\}/g,"$$0.00");