I can't find the documentation on what are the parameters for the always() method.

Right now, I'm just using:

$.post("foo.do", {
    ...
}, function(data) {
    ...
}).fail(function(jqXHR, textStatus, errorThrown) {
    ...
}).always(function() {
    ...
});

I can't find the documentation on what are the parameters for the always() method.

Right now, I'm just using:

$.post("foo.do", {
    ...
}, function(data) {
    ...
}).fail(function(jqXHR, textStatus, errorThrown) {
    ...
}).always(function() {
    ...
});

• javascript
• jquery

• See also api.jquery./jquery.ajax jqXHR.always(function( data|jqXHR, textStatus, jqXHR|errorThrown ) { }); – Mike Commented Oct 11, 2014 at 19:01

1 Answer 1

The documentation is in jqXHR section of the $.ajax entry. ¹

The parameters are as follows:

jqXHR.always(function( data|jqXHR, textStatus, jqXHR|errorThrown ) { });

• If an error occurred:

  jqXHR.always(function( jqXHR, textStatus, errorThrown ) { });
  

• And otherwise:

  jqXHR.always(function( data, textStatus, jqXHR ) { });
  

Notes

1. Thanks to Mike's ment.