var name = document.getElementById("namebox").value;

if (array.includes(name) == false) {
   alert(name + " is not in record.")
}

that didn't work and will always return false, how to express the check in other ways? please enlighten, thank you very much

var name = document.getElementById("namebox").value;

if (array.includes(name) == false) {
   alert(name + " is not in record.")
}

that didn't work and will always return false, how to express the check in other ways? please enlighten, thank you very much

• javascript
• arrays
• loops

• what browser did that not work in? – Jaromanda X Commented Jun 9, 2017 at 4:35
• This question is already answered here – Parag Jadhav Commented Jun 9, 2017 at 4:35
• Can you show your Array and working snippet – prasanth Commented Jun 9, 2017 at 4:35
• codepen.io's default engine – Nate Commented Jun 9, 2017 at 4:35
• codepen.io's default engine what is this a response to? .... again, what browser did that not work in – Jaromanda X Commented Jun 9, 2017 at 4:38

2 Answers 2

because your array is like

[ "name1,score1", "name2,score2"]

searching for "name1" using includes wont work

you'll want something like

if (!array.some(item => item.split(',')[0] === name)) {
    alert(name + " is not in record.")
}

or in pre ES2015

if (!array.some(function (item) {
    return item.split(',')[0] === name;
})) {
    alert(name + " is not in record.");
}

or if your browser doesn't have Array.prototype.some

if (array.filter(function (item) {
    return item.split(',')[0] === name;
}).length === 0) {
    alert(name + " is not in record.");
}

You may try

if (array.indexOf(name) == -1) {
   alert(name + " is not in record.")
}