I am having two functions in my JavaScript code, and I want to perform some action on the basis of value returned by other function.

Here my code :-

function test1(){
    var radio = document.getElementByName('sample');
    for (i=0; i<radio.length; i++){
         //some code here
         return "some value on basis of above code"
    }
}

function test2(){
    var somevariable = globllysetValue;
    var returnValue = return test1();
    // some code and work according to the value in returnValue
}

Well I know return in function test2 is not correct. so what can I do here NOW????

Edit

Here what I am Trying to do... but it do not seem to be working /

EDIT2 ----- The corrected and working fiddle... / Thanks to all :)

I am having two functions in my JavaScript code, and I want to perform some action on the basis of value returned by other function.

Here my code :-

function test1(){
    var radio = document.getElementByName('sample');
    for (i=0; i<radio.length; i++){
         //some code here
         return "some value on basis of above code"
    }
}

function test2(){
    var somevariable = globllysetValue;
    var returnValue = return test1();
    // some code and work according to the value in returnValue
}

Well I know return in function test2 is not correct. so what can I do here NOW????

Edit

Here what I am Trying to do... but it do not seem to be working http://jsfiddle/U6RjY/7/

EDIT2 ----- The corrected and working fiddle... http://jsfiddle/U6RjY/9/ Thanks to all :)

• javascript

1 Answer 1

function test1(){
    var radio = document.getElementByName('sample');
     for (i=0; i<radio.length; i++){
         //some code here
         return "some value on basis of above code"
    }
}

function test2(){
    var somevariable = globllysetValue;
    var returnValue = test1();
    // some code and work according to the value in returnValue
}

Just remove the return.

You will notice however that in function test1, it will return the value on the first loop. So, it will stop executing.

Live example: http://jsfiddle/U6RjY/