Is it possible to look for arr elements in arrofobjs without a for loop? Since 'Buddy' is in both arr and arrofobjs, i'd expect found to return true

var arrofobjs = [ { type: 'Dog', name: 'Buddy', color: 'White' },
  { type: 'Cat', name: 'Misty', color: 'Black' },
  { type: 'Dog', name: 'Max', color: 'Black' }, ]
var arr = [ 'Buddy', 'Oscar' ]
var found = Object.values(arrofobjs).some(r=> arr.includes(r)) //returns false, but would return true if arrofobj was an object

Is it possible to look for arr elements in arrofobjs without a for loop? Since 'Buddy' is in both arr and arrofobjs, i'd expect found to return true

var arrofobjs = [ { type: 'Dog', name: 'Buddy', color: 'White' },
  { type: 'Cat', name: 'Misty', color: 'Black' },
  { type: 'Dog', name: 'Max', color: 'Black' }, ]
var arr = [ 'Buddy', 'Oscar' ]
var found = Object.values(arrofobjs).some(r=> arr.includes(r)) //returns false, but would return true if arrofobj was an object

• javascript
• arrays

• 3 I think you want arr.includes(r.name) << you need to look for the name attribute – Mark Commented Jul 23, 2018 at 7:19
• 2 I reckon that you should explicitly say "without a for loop", or maybe defining the kind of loop you want to avoid (while, forEach etc), because all answers here (some, includes, find etc...) do use loops internally. After all, if you stop to think, from the machine viewpoint this is impossible to do without looping. – Gerardo Furtado Commented Jul 23, 2018 at 7:27

3 Answers 3

You have to access the name property.

var arrofobjs = [ { type: 'Dog', name: 'Buddy', color: 'White' },
  { type: 'Cat', name: 'Misty', color: 'Black' },
  { type: 'Dog', name: 'Max', color: 'Black' }, ]
var arr = [ 'Buddy', 'Oscar' ]
var found = Object.values(arrofobjs).some(r => arr.includes(r.name))
console.log(found);

Since arrofobjs is an array, you can directly apply the some method by using destructing.

var arrofobjs = [ { type: 'Dog', name: 'Buddy', color: 'White' },
{ type: 'Cat', name: 'Misty', color: 'Black' },
{ type: 'Dog', name: 'Max', color: 'Black' }, ]
var arr = [ 'Buddy', 'Oscar' ]
var found = arrofobjs.some(({name}) => arr.includes(name))
console.log(found);

You were almost there. As arrofobjs is an array, you can directly iterate over it.

var arrofobjs = [ { type: 'Dog', name: 'Buddy', color: 'White' },{ type: 'Cat', name: 'Misty', color: 'Black' },{ type: 'Dog', name: 'Max', color: 'Black' }];
var arr = [ 'Buddy', 'Oscar' ];
var found = arrofobjs.some(({name})=> arr.includes(name));
console.log(found);

You could also use Array.prototype.find() method of array to find the record in array.

DEMO

var arrofobjs = [ { type: 'Dog', name: 'Buddy', color: 'White' },
  { type: 'Cat', name: 'Misty', color: 'Black' },
  { type: 'Dog', name: 'Max', color: 'Black' }],
  arr = ['Buddy', 'Oscar'];
  
arr.forEach(v=>console.log(arrofobjs.find(({name})=>name==v)||`${v} Not fond`));

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