I have the following chunk of code :

const createRecordMapping = () : unknown => mapper.createMap(Record, RecordDto)
  .forMember((d) => d.value,
    mapFrom((s) => GraphQLJSON.parseValue(s.value)));

Eslint error i am getting for it is :

Unsafe return of an any typed value @typescript-eslint/no-unsafe-return

What am I missing here?

I have the following chunk of code :

const createRecordMapping = () : unknown => mapper.createMap(Record, RecordDto)
  .forMember((d) => d.value,
    mapFrom((s) => GraphQLJSON.parseValue(s.value)));

Eslint error i am getting for it is :

Unsafe return of an any typed value @typescript-eslint/no-unsafe-return

What am I missing here?

• javascript
• typescript
• typescript-typings

• 2 Either d.value or GraphQLJSON.parseValue(s.value) produces any. The linting rule you have forbids returning any. – VLAZ Commented Jan 27, 2021 at 12:11

1 Answer 1

The code you wrote translates to this:

const createRecordMapping = (): unknown => mapper.createMap(Record, RecordDto)
  .forMember((d) => /*d.value, */mapFrom((s) => GraphQLJSON.parseValue(s.value)));

You probably wanted to chain the functions:

const createRecordMapping = (): unknown => mapper.createMap(Record, RecordDto)
  .forMember((d) => d.value)
  .mapFrom((s) => GraphQLJSON.parseValue(s.value) as unknown);

Also, the GraphQLJSON.parseValue probably does return any type, as it is parsing JSON.