I've created a mock social media website where users can ment and "like" posts, and so I want to have a button with a thumbs up that will toggle between "liked" and "not liked". Problem is, when I click, the state value (unliked) is joined by the setState value(liked) intead of replaced. Where am I going wrong?
import React, { useState } from 'react';
import ThumbUpIcon from '@material-ui/icons/ThumbUp';
const ThumbUpButton = {
backgroundColor: 'rgb(115, 250, 179)',
border: 'none',
borderRadius: '5px',
}
const ThumbStyle = {
backgroundColor: 'red',
border: 'none',
padding: '5px',
borderRadius: '5px',
margin: '1rem'
}
const Liker = () => {
const [thumb, setThumbUp] = useState(false);
return (
<>
<button style={{border: 'none', backgroundColor: 'transparent'}} onClick={() => setThumbUp(!thumb)}>
<ThumbUpIcon style={ThumbStyle} />
{thumb && <ThumbUpIcon style={ThumbUpButton} />}
</button>
</>
);
}
export default Liker;
I've created a mock social media website where users can ment and "like" posts, and so I want to have a button with a thumbs up that will toggle between "liked" and "not liked". Problem is, when I click, the state value (unliked) is joined by the setState value(liked) intead of replaced. Where am I going wrong?
import React, { useState } from 'react';
import ThumbUpIcon from '@material-ui/icons/ThumbUp';
const ThumbUpButton = {
backgroundColor: 'rgb(115, 250, 179)',
border: 'none',
borderRadius: '5px',
}
const ThumbStyle = {
backgroundColor: 'red',
border: 'none',
padding: '5px',
borderRadius: '5px',
margin: '1rem'
}
const Liker = () => {
const [thumb, setThumbUp] = useState(false);
return (
<>
<button style={{border: 'none', backgroundColor: 'transparent'}} onClick={() => setThumbUp(!thumb)}>
<ThumbUpIcon style={ThumbStyle} />
{thumb && <ThumbUpIcon style={ThumbUpButton} />}
</button>
</>
);
}
export default Liker;
Share
Improve this question
asked Aug 28, 2021 at 22:25
MarkohanMarkohan
1422 silver badges12 bronze badges
1
-
1
Your state seems to be fine but it seems like you don't want to render the first
ThumbUpIcon
ifthumb
istrue
? Try changing the first one to{!thumb && <ThumbUpIcon style={ThumbStyle} />}
– digitalbreed Commented Aug 28, 2021 at 22:28
4 Answers
Reset to default 3If I understand your question, you are asking why both a thumbs up and thumbs down sometimes render at the same time. This is because you unconditionally render the thumbs up, and conditionally render the thumbs down.
You should render one or the other. Since it's the same ponent and you are only swapping the style, then conditionally apply one or the other styling.
Additionally, it is mon to use a functional state update when toggling a boolean state value since the next state necessarily depends on the previous state, i.e. thumb => !thumb
. This avoids stale state enclosures in callbacks.
<button
style={{
border: 'none',
backgroundColor: 'transparent'
}}
onClick={() => setThumbUp(thumb => !thumb)}
>
<ThumbUpIcon style={thumb ? ThumbStyle : ThumbUpButton} />
</button>
Please set the value directly
onClick={() => setThumbUp(!thumb)}
change this might work using functinal set state
onClick={() => setThumbUp(s=>!s)}
Firstly you should update your state via callbacksetThumbUp ((thumb) => !thumb)
, secondly you have the problem in this line <ThumbUpIcon style={ThumbStyle} />
, this JSX get rendered either the button like clicked or not, so you have to put a condition on it:
import React, { useState } from 'react';
import ThumbUpIcon from '@material-ui/icons/ThumbUp';
const ThumbUpButton = {
backgroundColor: 'rgb(115, 250, 179)',
border: 'none',
borderRadius: '5px',
};
const ThumbStyle = {
backgroundColor: 'red',
border: 'none',
padding: '5px',
borderRadius: '5px',
margin: '1rem',
};
const Liker = () => {
const [thumb, setThumbUp] = useState(false);
const style = thumb ? ThumbUpButton : ThumbStyle;
return (
<>
<button
style={{ border: 'none', backgroundColor: 'transparent' }}
onClick={() => setThumbUp((thumb) => !thumb)}
>
<ThumbUpIcon style={style} />
</button>
</>
);
};
export default Liker;