call to split on a variable causes a "Object doesn't support this property or method" exception and I don't know why. Here's my code:

function getKontaktPersonen(kontaktSelectBox) {
   var kontaktPersonen = [];
   var id_and_name = kontaktSelectBox.attr('id');
   var id_part = getID_PartFromName(id_and_name);
   var textboxname;
   var selectboxname;
   if (kontaktSelectBox.attr('class') == 'kontaktSelectBox') {

        textboxname = "TextBoxKunde" + id_part;
        selectboxname = "SelectBoxKontaktPerson" + id_part;
    } else if (kontaktSelectBox.attr('class') == 'NewkontaktSelectBox') {
        textboxname = "NewTextBoxKunde" + id_part;
        selectboxname = "NewSelectBoxKontaktPerson" + id_part;
    } else {
        return false;
    }
    var kundeBox = $('#' + textboxname);
    var kundeBoxVal = kundeBox.val();
    if (kundeBoxVal != '' && kundeBoxVal != null) {
     var adr_id = kundeBoxVal.split(';')[1];
      //here es an ajax call
      //[...]
    }
}

call to split on a variable causes a "Object doesn't support this property or method" exception and I don't know why. Here's my code:

function getKontaktPersonen(kontaktSelectBox) {
   var kontaktPersonen = [];
   var id_and_name = kontaktSelectBox.attr('id');
   var id_part = getID_PartFromName(id_and_name);
   var textboxname;
   var selectboxname;
   if (kontaktSelectBox.attr('class') == 'kontaktSelectBox') {

        textboxname = "TextBoxKunde" + id_part;
        selectboxname = "SelectBoxKontaktPerson" + id_part;
    } else if (kontaktSelectBox.attr('class') == 'NewkontaktSelectBox') {
        textboxname = "NewTextBoxKunde" + id_part;
        selectboxname = "NewSelectBoxKontaktPerson" + id_part;
    } else {
        return false;
    }
    var kundeBox = $('#' + textboxname);
    var kundeBoxVal = kundeBox.val();
    if (kundeBoxVal != '' && kundeBoxVal != null) {
     var adr_id = kundeBoxVal.split(';')[1];
      //here es an ajax call
      //[...]
    }
}

• javascript
• jquery

• make sure that it is not null – Diode Commented Feb 9, 2012 at 8:21
• @Luke. What version? Try the code in Chrome or FF. – gdoron Commented Feb 9, 2012 at 9:16

1 Answer 1

If the selector didn't find any element the val function will return undefined Try this:

if (kundeBoxVal) {
     var adr_id = kundeBoxVal.split(';')[1];
 }