I want to get 11 character post id based on Regex expression. In my code I added two Instagram URL written in different ways, I want a proper Regex expression which gives me 11 characters post id. The Regex expression I am using is not giving proper results.
JsFiddle: /
Code:
<body onload="myFunction()">
</body>
<script>
function myFunction() {
var userURL = "/";
var userURL1 = "/";
var regExp = /(https?:\/\/www\.)?instagram\(\/p\/\w+\/?)/;
var match = userURL.match(regExp);
var match1 = userURL.match(regExp);
alert(match);
alert(match1);
}</script>
I want to get 11 character post id based on Regex expression. In my code I added two Instagram URL written in different ways, I want a proper Regex expression which gives me 11 characters post id. The Regex expression I am using is not giving proper results.
JsFiddle: https://jsfiddle/z5huq2aL/
Code:
<body onload="myFunction()">
</body>
<script>
function myFunction() {
var userURL = "https://www.instagram./p/CBnwdW5n2VA/";
var userURL1 = "https://www.instagram./angelinajolie_offiicial/p/CBnwdW5n2VA/";
var regExp = /(https?:\/\/www\.)?instagram\.(\/p\/\w+\/?)/;
var match = userURL.match(regExp);
var match1 = userURL.match(regExp);
alert(match);
alert(match1);
}</script>
-
3
You don't need most of that regex. Just
/\/p\/(.*?)\//will do. Then just getmatch[1]for the sub-pattern (which is the ID you want). – Niet the Dark Absol Commented Jul 15, 2020 at 10:34
2 Answers
Reset to default 4Use a single capturing group and place the /p/ and the trailing / outside of the group.
If you want to match 11 word chars, use \w{11}, else \w+ would suffice.
Assuming the url does not contain whitespace chars, you could use \S*? to match until the first occurrence of /p/
Note that the first part is optional and is not anchored. It matches the http://www. if it is there, but when it is not there, or something else is there, you could still get a partial match for the rest of the pattern.
(?:https?:\/\/www\.)?instagram\.\S*?\/p\/(\w{11})\/?
Regex demo
var userURL = "https://www.instagram./p/CBnwdW5n2VA/";
var userURL1 = "https://www.instagram./angelinajolie_offiicial/p/CBnwdW5n2VA/";
var regExp = /(?:https?:\/\/www\.)?instagram\.\S*?\/p\/(\w{11})\/?/;
var match = userURL.match(regExp);
var match1 = userURL.match(regExp);
console.log(match[1]);
console.log(match1[1]);Below code should solve your issue:
function myFunction() {
var userURL = "https://www.instagram./p/CBnwdW5n2VA/";
var userURL1 = "https://www.instagram./angelinajolie_offiicial/p/CBnwdW5n2VA/";
var regExp = /\/p\/(.*?)\//;
var match = userURL.match(regExp);
var match1 = userURL.match(regExp);
alert(match[1]);
alert(match1[1]);
}
working fiddle here: https://jsfiddle/narkhedetusshar/u2xgh0r5/