I am fetching Google in a gadget using this code:
<html>
<head>
<title>Browser</title>
</head>
<body onload= "getListCollection()" style="width:900px; height:900px;" >
<div id="listAttributes" style="width:400px; height:400px;" ></div>
<script>
function getListCollection() {
var url = ""
xmlhttp = new XMLHttpRequest();
xmlhttp.open('GET',url,true, 'user', 'password');
xmlhttp.onreadystatechange = function()
{
if(xmlhttp.readyState == 4);
{
document.getElementById("listAttributes").innerHTML = xmlhttp.responseText
}
}
xmlhttp.send(null);
}
</script>
</body>
</html>
I wonder how can I do the same thing using $ajax?
I looked at different examples but I don't know how they gonna fit in this situation. Or if you can post some nice $ajax tutorials please.
When I change it to this, it doesn't work:
<html>
<head>
<title>Browser</title>
</head>
<body onload= "getListCollection()" style="width:900px; height:900px;" >
<div id="listAttributes" style="width:400px; height:400px;" ></div>
<script src=".5.1/jquery.min.js">
$.ajax({
url : '',
type : 'GET',
success : function(data){
$('#listAttributes').html(data);
}
});
</script>
</body>
</html>
Nothing es up on the page.
I am fetching Google in a gadget using this code:
<html>
<head>
<title>Browser</title>
</head>
<body onload= "getListCollection()" style="width:900px; height:900px;" >
<div id="listAttributes" style="width:400px; height:400px;" ></div>
<script>
function getListCollection() {
var url = "https://www.google.co.uk"
xmlhttp = new XMLHttpRequest();
xmlhttp.open('GET',url,true, 'user', 'password');
xmlhttp.onreadystatechange = function()
{
if(xmlhttp.readyState == 4);
{
document.getElementById("listAttributes").innerHTML = xmlhttp.responseText
}
}
xmlhttp.send(null);
}
</script>
</body>
</html>
I wonder how can I do the same thing using $ajax?
I looked at different examples but I don't know how they gonna fit in this situation. Or if you can post some nice $ajax tutorials please.
When I change it to this, it doesn't work:
<html>
<head>
<title>Browser</title>
</head>
<body onload= "getListCollection()" style="width:900px; height:900px;" >
<div id="listAttributes" style="width:400px; height:400px;" ></div>
<script src="http://ajax.googleapis./ajax/libs/jquery/1.5.1/jquery.min.js">
$.ajax({
url : 'https://www.google.co.uk',
type : 'GET',
success : function(data){
$('#listAttributes').html(data);
}
});
</script>
</body>
</html>
Nothing es up on the page.
Share Improve this question edited Aug 6, 2012 at 11:57 Shegit Brahm 7132 gold badges9 silver badges22 bronze badges asked May 18, 2012 at 14:24 Muhammad RajaMuhammad Raja 2,0103 gold badges29 silver badges46 bronze badges 2-
1
Do you mean
$.ajax()
? Start with the documentation. – jrummell Commented May 18, 2012 at 14:26 -
What is
$ajax
? You've tagged thisjquery
so do you mean$.ajax
? Have you tried looking at the tutorials on the jQuery site?! – Quentin Commented May 18, 2012 at 14:26
4 Answers
Reset to default 6Here's a jQuery version of the code:
$.ajax({
url : 'https://www.google.co.uk', //cross-domain? this won't work
username : 'user',
password : 'password',
type : 'GET', //default is GET, but i put it here to clarify
success : function(data){
$('#listAttributes').html(data);
}
});
For more details and settings, read the jQuery.ajax()
documentation
Something like that:
$.ajax({
url : "https://www.google.co.uk",
type : "get",
username : "user",
password : "password",
success : function(data) {
document.getElementById("listAttributes").innerHTML = data;
}
});
However, your code most probably won't work since you are trying to access the external resource (i.e. not your domain).
Check the JQuery Ajax documentation for further details.
$.ajax({
url: url,
username: 'user',
password: 'password'
}).done(function (responseText) {
document.getElementById('listAttributes').innerHTML = responseText;
//or
$("#listAttributes").html(responseText);
});
By default, .ajax
will use the GET method and be asynchronous, so I omitted those settings. If you don't need the username/password, I would use $.get()
.
It's really simple and shorter than the pure JavaScript version, here it is:
function getListCollection() {
$.ajax({
url: "https://www.google.co.uk",
username: "user",
password: "password",
success: function(data){
$('listAttributes').html(data);
}
});
}
The request is only accepted if the site supports cross-domain origin. Check the jQuery.ajax() documentation here.