Trying to do something simple, but not sure what I am doing wrong.

I simply want to call a function with number arguments and push those numbers into a new array...

function someFunction(n){
  var newArray = new Array(n);
  for(var i=0; i < n.length; i++){
    newArray += n[i];
  }
  return newArray;
}

console.log(someFunction(3,5,4,5));

Trying to do something simple, but not sure what I am doing wrong.

I simply want to call a function with number arguments and push those numbers into a new array...

function someFunction(n){
  var newArray = new Array(n);
  for(var i=0; i < n.length; i++){
    newArray += n[i];
  }
  return newArray;
}

console.log(someFunction(3,5,4,5));

Here is bin

• javascript
• arrays

• stackoverflow./questions/2141520/… take a look at this - here is explained how to deal with a variable number of arguments, which is, if I understand good, your main issue. And also at this w3schools./jsref/jsref_push.asp - here is how to push elements to a javascript array. – Rafael Korbas Commented Feb 1, 2016 at 21:29
• 3 Start with MDN; you have a problem on nearly every line here. – Evan Davis Commented Feb 1, 2016 at 21:29

4 Answers 4

This will get those numbers into the array for you. And it will do it for unlimited numbers supplied: https://jsfiddle/a9umss9a/3/

function someFunction(){
  var newArray = [];
  for(var i=0; i < arguments.length; i++){
    newArray.push(arguments[i]);
  }
  return newArray;
}

console.log(someFunction(3,5,4,5));

console.log(someFunction(3,5,4,5,100,200,300,400,500));

You can do this as a one-liner:

function toArray() {
    return [].slice.call(arguments);
}

Here's the breakdown of issues in your code.

function someFunction(n){ // this captures the FIRST argument as n
  var newArray = new Array(n); // this creates a new Array of length n (in your case, 3, which is not accurate
  for(var i=0; i < n.length; i++){ // n is a number and has no length property
    newArray += n[i]; // newArray is an array, so you must push to it; the + operator makes no sense
  }
  return newArray;
}

someFunction requires 1 input of type array, not 4 inputs:

function someFunction(n){
  var newArray = [];
  for(var i=0; i < n.length; i++){
    newArray.push(n[i]);
  }
  return newArray;
}

console.log(someFunction([3,5,4,5]));

A solution with direct building of an array.

function someFunction() {
    return Array.apply(null, arguments);
}

document.write('<pre>' + JSON.stringify(someFunction(3, 5, 4, 5), 0, 4) + '</pre>');