I have a plex Jquery-UI based dialog and I want to provide a SVG image as background. I tried to make this work in a simple test file first and it does not work though the SVG, as a standalone image, works fine. Here is the simplified code:
<script>
$(document).ready(function () {
svg = "<svg width='400' height='400' fill='url(#grad1)' \
xmlns=''> <rect id='bkgrect' width='400' \
height='400' style='fill:'url(#grad1)'; stroke-width:3;'/> <defs>\
<linearGradient id='grad1' x1='0' y1='20%' x2='0%' y2='100%'> \
<stop id='stop1' offset='0%' stop-color='blue'/> <stop offset='100%' \
stop-color='white'/> </linearGradient> </defs> </svg>";
svgBase64 = btoa(svg);
bkgrndImg = "url('data:image/svg+xml;base64,"+ svgBase64 +"')";
$('#testDiv').css('background-image', bkgrndImg);
});
</script>
</head>
<body>
<div id='testDiv' style="border:2px solid red;width:400px;height:400px;
position:absolute;left:100px;top:100px;"> Some SVG Div </div>
<svg ... /svg>
The svg ... /svg is the same svg as used in the background and it displays properly.
After looking at various solutions, I have relied primarily on this post. I also tried to simulate background SVG image by using z-index and positioning the image in the Div as an image but thats not a good fix. I want to get SVG as a background image to work smoothly across browsers because at least SVG gradients are well supported in all modern browsers and I think the time for SVG's potential to be fully realized has finally arrived.
I have a plex Jquery-UI based dialog and I want to provide a SVG image as background. I tried to make this work in a simple test file first and it does not work though the SVG, as a standalone image, works fine. Here is the simplified code:
<script>
$(document).ready(function () {
svg = "<svg width='400' height='400' fill='url(#grad1)' \
xmlns='http://www.w3/2000/svg'> <rect id='bkgrect' width='400' \
height='400' style='fill:'url(#grad1)'; stroke-width:3;'/> <defs>\
<linearGradient id='grad1' x1='0' y1='20%' x2='0%' y2='100%'> \
<stop id='stop1' offset='0%' stop-color='blue'/> <stop offset='100%' \
stop-color='white'/> </linearGradient> </defs> </svg>";
svgBase64 = btoa(svg);
bkgrndImg = "url('data:image/svg+xml;base64,"+ svgBase64 +"')";
$('#testDiv').css('background-image', bkgrndImg);
});
</script>
</head>
<body>
<div id='testDiv' style="border:2px solid red;width:400px;height:400px;
position:absolute;left:100px;top:100px;"> Some SVG Div </div>
<svg ... /svg>
The svg ... /svg is the same svg as used in the background and it displays properly.
After looking at various solutions, I have relied primarily on this post. I also tried to simulate background SVG image by using z-index and positioning the image in the Div as an image but thats not a good fix. I want to get SVG as a background image to work smoothly across browsers because at least SVG gradients are well supported in all modern browsers and I think the time for SVG's potential to be fully realized has finally arrived.
Share Improve this question edited May 23, 2017 at 11:59 CommunityBot 11 silver badge asked Jan 5, 2016 at 13:38 SunnySunny 10.1k12 gold badges55 silver badges91 bronze badges 5-
2
Do you have to have it as base64? Could you not just externally link to the svg like a normal image?
background: url(../images/fancy.svg)
If the svg is not dynamic I find it easier to maintain as a normal file. – Lex Commented Jan 5, 2016 at 13:46 - 1 @Lex I want to have it inline so I can change it dynamically with JS. – Sunny Commented Jan 5, 2016 at 13:48
- the post you have mentioned is asking to escape # which you did not do as I see # replaced with %23. – wui Commented Jan 5, 2016 at 13:53
- @koded I am using the answer provided by Mike Tommasi though it is not the accepted answer in that post. I found that answer to be more natural. – Sunny Commented Jan 5, 2016 at 13:55
- PLEASE SEE MY COMMENTS TO THE ACCEPTED ANSWER. THEY MAY BE HELPFUL... – Sunny Commented Jan 6, 2016 at 4:01
3 Answers
Reset to default 3Here is an alternative. You could use CSS classes then in your Javascript just change its class to toggle between different backgrounds. See example below:
$('button').click(function() {
$('#testDiv').toggleClass('gradient1 gradient2');
});
.gradient1 {
background: #4e8ef7 url(data:image/svg+xml;base64,Cjxzdmcgd2lkdGg9IjUwMHB4IiBoZWlnaHQ9IjUwMHB4IiB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciPgogPGRlZnM+CiAgPGxpbmVhckdyYWRpZW50IGlkPSJncmFkaWVudCIgeDE9IjAuNSIgeTE9IjAiIHgyPSIwLjUiIHkyPSIxIj4KICAgPHN0b3Agb2Zmc2V0PSIwIiBzdG9wLWNvbG9yPSIjMjk2YWQ0IiAvPgogICA8c3RvcCBvZmZzZXQ9IjEiIHN0b3AtY29sb3I9IiM0ZThlZjciIC8+CiAgPC9saW5lYXJHcmFkaWVudD4KIDwvZGVmcz4KIDxnPgogIDxyZWN0IGZpbGw9InVybCgjZ3JhZGllbnQpIiBzdHJva2Utd2lkdGg9IjAiIHg9IjAiIHk9IjAiIHdpZHRoPSI1MDAiIGhlaWdodD0iNTAwIiAvPgogPC9nPgo8L3N2Zz4KICAgIA==) top repeat-x;
background-size: contain;
}
.gradient2 {
background: #7962ff url(data:image/svg+xml;base64,Cjxzdmcgd2lkdGg9IjUwMHB4IiBoZWlnaHQ9IjUwMHB4IiB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciPgogPGRlZnM+CiAgPGxpbmVhckdyYWRpZW50IGlkPSJncmFkaWVudCIgeDE9IjAuNSIgeTE9IjAiIHgyPSIwLjUiIHkyPSIxIj4KICAgPHN0b3Agb2Zmc2V0PSIwIiBzdG9wLWNvbG9yPSIjM2ZiYWUyIiAvPgogICA8c3RvcCBvZmZzZXQ9IjEiIHN0b3AtY29sb3I9IiM3OTYyZmYiIC8+CiAgPC9saW5lYXJHcmFkaWVudD4KIDwvZGVmcz4KIDxnPgogIDxyZWN0IGZpbGw9InVybCgjZ3JhZGllbnQpIiBzdHJva2Utd2lkdGg9IjAiIHg9IjAiIHk9IjAiIHdpZHRoPSI1MDAiIGhlaWdodD0iNTAwIiAvPgogPC9nPgo8L3N2Zz4KICAgIA==) top repeat-x;
background-size: contain;
}
<script src="https://ajax.googleapis./ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button>Change gradient</button>
<div class="gradient1" id='testDiv' style="border:2px solid red;width:400px;height:400px;
position:absolute;left:100px;top:100px;">Some SVG Div</div>
Or
$('button').click(function() {
var mySVG = "<svg xmlns='http://www.w3/2000/svg' width='10' height='10'><linearGradient id='gradient'><stop offset='10%' stop-color='#EEE'/><stop offset='90%' stop-color='#fcc'/> </linearGradient><rect fill='url(#gradient)' x='0' y='0' width='100%' height='100%'/></svg>";
var mySVG64 = window.btoa(mySVG);
document.getElementById('testDiv').style.backgroundImage = "url('data:image/svg+xml;base64," + mySVG64 + "')";
});
<script src="https://ajax.googleapis./ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button>Change gradient</button>
<div class="gradient1" id='testDiv' style="border:2px solid red;width:400px;height:400px;
position:absolute;left:100px;top:100px;">Some SVG Div</div>
EDIT Added OPs gradient color.
Problem is with syntax :
Change style='fill:'url(#grad1)'; stroke-width:3;'
to style='fill:url(#grad1);stroke-width:3;'
-- remove the '
around the url()
and it should work
$(document).ready(function() {
var mySVG = "<svg xmlns='http://www.w3/2000/svg' width='400' height='400' fill='url(#grad1)'><rect id='bkgrect' width='400' height='400' style='fill:url(#grad1);stroke-width:3;' /><linearGradient id='grad1' x1='0' y1='20%' x2='0%' y2='100%'><stop offset='0%' stop-color='blue'/><stop offset='100%' stop-color='white'/> </linearGradient><rect fill='url(#grad1)' x='0' y='0' width='100%' height='100%'/></svg>";
var mySVG64 = window.btoa(mySVG);
document.getElementById('testDiv').style.backgroundImage = "url('data:image/svg+xml;base64," + mySVG64 + "')";
});
<script src="https://ajax.googleapis./ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id='testDiv' style="border:2px solid red;width:400px;height:400px;
position:absolute;left:100px;top:100px;">Some SVG Div</div>
Read more here about styling properties
You could try not using the base64 encoding, as described here:
https://css-tricks./probably-dont-base64-svg/
.bg {
background: url('data:image/svg+xml;utf8,<svg ...> ... </svg>');
}
However, if you only want the gradient, you could just use the CSS background-image: linear-gradient(blue, white) syntax.
It doesn't work because you're missing xmlns:xlink="http://www.w3/1999/xlink"
on the root <svg>
element.
I tried running mine as a standalone .svg
file and got the error Namespace prefix xlink for href on ... is not defined
, which led me to this question.