I'm trying to load some data via jQuery.getJSON() but it does not work:

here is my JSON:

{didwork=true,userid=123}

or it is

{didwork=false,userid=0}

here is my Javascript:

$.ajax({
  data["username"] = "u"
  data["password"] = "p";
  url: .php,
  dataType: 'json',
  data: data,
  success: function(json){
    //fill it into div
  }
});

I'm trying to load some data via jQuery.getJSON() but it does not work:

here is my JSON:

{didwork=true,userid=123}

or it is

{didwork=false,userid=0}

here is my Javascript:

$.ajax({
  data["username"] = "u"
  data["password"] = "p";
  url: https://www.myurl./json.php,
  dataType: 'json',
  data: data,
  success: function(json){
    //fill it into div
  }
});

• javascript
• jquery
• ajax
• json

• 3 If you're ever curious if your JSON is or is not right, I'd higly remend using JsonLint.. – Erik Philips Commented Apr 28, 2012 at 15:34
• 1 That code is a syntax error; it cannot possibly work. You should always have your JavaScript console open. – Pointy Commented Apr 28, 2012 at 15:34

2 Answers 2

your json string is wrong. it has to be

{"didwork":true,"userid":123}

or

{"didwork":false,"userid":0}

never use = and always use "

Your javascript is wrong..

you need to move the data initialization outside the ajax call..
plus the url needs to be quoted.. (between ')

var data = {};
data["username"] = "u";
data["password"] = "p";

this could also be represented with

var data = {'username': 'u', 'password': 'p'};

and the call

$.ajax({
  url: 'https://www.myurl./json.php',
  dataType: 'json',
  data: data,
  success: function(json){
    //fill it into div
  }
});

Your json is wrong

should be {"didwork":true,"userid":123}

If the url is to a different site then the one making the call it will fail due to same origin policy