How to check if arrays
has array
?
var arrays = [[1, 1], [2, 2]];
var array = [1,1];
[1, 1] === [1, 1]; // false
arrays.includes(array); // false
arrays.indexOf(array); // -1
How to check if arrays
has array
?
var arrays = [[1, 1], [2, 2]];
var array = [1,1];
[1, 1] === [1, 1]; // false
arrays.includes(array); // false
arrays.indexOf(array); // -1
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edited Dec 25, 2021 at 23:00
Leau
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asked Mar 26, 2013 at 0:45
TukkanTukkan
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- 2 This really helps. stackoverflow./questions/12604062/… – Near Commented Mar 26, 2013 at 0:53
-
1
It returns
-1
becauseb
isn't ina
.[1, 1] == [1, 1]
isfalse
in JavaScript. – Blender Commented Mar 26, 2013 at 0:54
3 Answers
Reset to default 4indexOf pares using strict equality (===
). Your elements would have to be the exact same object.
so
var a = [1,1];
var b = [a,[1,2]];
b.indexOf(a)// 0
because a === a
but
b.indexOf([1,1])// -1
because [1,1] is a different object than a
so they're not strictly equal.
MDN Docs
To do what you want to do you'll need to do something more involved. You can loop over the values and use something like whats in this question's answers to do the parison
indexOf
returns -1 if it does not find a match in the array. Your array a
does not contain element b
.
EDIT:
To clarify on what @JonathanLonowski said, the reason there is not a match is because you are doing a strict parison, paring the references, not the values.
<Array>.some
method tests whether at least one array in the multi-dimensional array passes the test implemented by the provided function.
<Array>.every
method tests whether all array items in the array pass the test implemented by the provided function.
These two methods bined make it possible to check if all the items of an array in the multidimensional one are worth those of that sought.
const checkArray = (arrays, array) => arrays.some(a => {
return (a.length > array.length ? a : array).every((_, i) => a[i] === array[i]);
});
const arrays = [[0, 1], [2, 2], [0, 3, 2, 1]];
[
[0, 1], // true
[2, 2], // true
[0, 3, 2, 1], // true
[1, 0, 3, 2, 1], // false
[2, 2, 1], // false
[0, 0], // false
[1, 2], // false
[0, 1, 2] // false
].forEach(array => {
console.log(checkArray(arrays, array));
});