In Terminal, when I try to run % node example.js why do I get -bash: fg: %: no such job?

I've installed Node.js. I've saved example.js with the example code:

var http = require('http');
http.createServer(function (req, res) {
  res.writeHead(200, {'Content-Type': 'text/plain'});
  res.end('Hello World\n');
}).listen(1337, '127.0.0.1');
console.log('Server running at http://127.0.0.1:1337/');

This is following the webserver example on the landing page of /.

In Terminal, when I try to run % node example.js why do I get -bash: fg: %: no such job?

I've installed Node.js. I've saved example.js with the example code:

var http = require('http');
http.createServer(function (req, res) {
  res.writeHead(200, {'Content-Type': 'text/plain'});
  res.end('Hello World\n');
}).listen(1337, '127.0.0.1');
console.log('Server running at http://127.0.0.1:1337/');

This is following the webserver example on the landing page of http://nodejs/.

• javascript
• node.js
• bash
• terminal

• 3 % is used to define a job, it expects a job identifier(number,string,etc) after it. Also i think on that website they are using % as the prompt. Try just node example.js – user3442743 Commented Jul 22, 2014 at 7:16

2 Answers 2

Running node example.js is successful without the %.

node example.js results in: Server running at http://127.0.0.1:1337/

% is used to define a job, it expects a job identifier(number,string,etc) after it. Also i think on that website they are using % as the prompt. Try just node example.js – Jidder

Credit: Jidder

% is often used as the prompt, I had a similar situation when running a mongo shell mand from mongolab.

Run the mand after the %.