I need regular expression that detect

1- any english letter or

2- any arabic letter or

3- both or

4- any number in between ( or start or end place dose not matter)

5-Maximum length can be 30.

and make sure it dose not have special characters except (they can appear any where)

@ , = % $ # & _

My Solution: I use this regular expression:

    var regex = /^([a-zA-Z0-9\s@,=%$#&_\u0600-\u06FF]).{0,30}$/;
    var result = regex.test('happy- - - /*  */ % ! ~');
    console.log(result);//prints true and it should print false because of ! and other special characters not allowed

The Problem

My solution is not correct

My References For arabic i use check here # 13 in the list Second reference Third reference

U+0600–U+06FF

/

I need regular expression that detect

1- any english letter or

2- any arabic letter or

3- both or

4- any number in between ( or start or end place dose not matter)

5-Maximum length can be 30.

and make sure it dose not have special characters except (they can appear any where)

@ , = % $ # & _

My Solution: I use this regular expression:

    var regex = /^([a-zA-Z0-9\s@,=%$#&_\u0600-\u06FF]).{0,30}$/;
    var result = regex.test('happy- - - /*  */ % ! ~');
    console.log(result);//prints true and it should print false because of ! and other special characters not allowed

The Problem

My solution is not correct

My References For arabic i use check here # 13 in the list Second reference Third reference

U+0600–U+06FF

https://jsfiddle/shareefhiasat/bdm99b1x/

• javascript
• regex
• match

• 2 You quantified a dot. Remove the dot. – Wiktor Stribiżew Commented Jul 28, 2017 at 17:06
• Seems strange to use English characters. Do you mean Latin instead ? – user557597 Commented Jul 28, 2017 at 17:47
• @WiktorStribiżew yes i think its working why you did not post that simple answer , please do and i will accept. and for down vote ! y. – shareef Commented Jul 28, 2017 at 20:32
• Isn't it a typo? I suggest that you should remove the post. – Wiktor Stribiżew Commented Jul 28, 2017 at 20:33
• You used the Arabic block which range from 600-6FF. But, there are more Arabic blocks. [\p{Block=Arabic}\p{Block=Arabic_Extended_A}\p{Block=Arabic_Mathematical_Alphabetic_Symbols}\p{Block=Arabic_Presentation_Forms_A}\p{Block=Arabic_Presentation_Forms_B}\p{Block=Arabic_Supplement}] – user557597 Commented Jul 28, 2017 at 20:51

2 Answers 2

You just need to quantify the group, not the dot.
Here is a regex for all Arabic (Unicode 9) characters.
Note that you've just included some English characters, did you mean Latin ?

^(?:[a-zA-Z0-9\s@,=%$#&_\u0600-\u06FF\u0750-\u077F\u08A0-\u08FF\uFB50-\uFDCF\uFDF0-\uFDFF\uFE70-\uFEFF]|(?:\uD802[\uDE60-\uDE9F]|\uD83B[\uDE00-\uDEFF])){0,30}$

https://jsfiddle/pydbqxgb/

Expanded

 ^     
 (?:
      [a-zA-Z0-9\s@,=%$#&_\u0600-\u06FF\u0750-\u077F\u08A0-\u08FF\uFB50-\uFDCF\uFDF0-\uFDFF\uFE70-\uFEFF] 
   |  
      (?:
           \uD802 [\uDE60-\uDE9F] 
        |  \uD83B [\uDE00-\uDEFF] 
      )
 ){0,30}
 $ 

An alternative, this uses basic non-control (whitespace only) Latin.

^(?:[\u0009-\u000D\u001C-\u007E\u0600-\u06FF\u0750-\u077F\u08A0-\u08FF\uFB50-\uFDCF\uFDF0-\uFDFF\uFE70-\uFEFF]|(?:\uD802[\uDE60-\uDE9F]|\uD83B[\uDE00-\uDEFF])){0,30}$

https://jsfiddle/st60dyve/

Expanded

 ^     
 (?:
      [\u0009-\u000D\u001C-\u007E\u0600-\u06FF\u0750-\u077F\u08A0-\u08FF\uFB50-\uFDCF\uFDF0-\uFDFF\uFE70-\uFEFF] 
   |  
      (?:
           \uD802 [\uDE60-\uDE9F] 
        |  \uD83B [\uDE00-\uDEFF] 
      )
 ){0,30}
 $ 

simply use this Regex for alpha numeric English, Arabic and without space with minimum 5 characters.

[0-9a-zA-Z\u0600-\u06FF]