is it possible to skip values while using the map method in javascript?
so for example
<!DOCTYPE html>
<html>
<body>
<button onclick="myFunction()">Try it</button>
<p id="demo"></p>
<script>
var numbers = [4, 9, 16, 25];
function myFunction() {
x = document.getElementById("demo")
x.innerHTML = numbers.map(Math.sqrt);
}
</script>
</body>
</html>
this code is going to output 2,3,4,5
but can you make it output 2,4 so it checks the first value in the array then skips the second until the end
or
3,5 so it skips the first value in the array then checks the second value.
is this possible using the map method? or do I have to use a for loop?
is it possible to skip values while using the map method in javascript?
so for example
<!DOCTYPE html>
<html>
<body>
<button onclick="myFunction()">Try it</button>
<p id="demo"></p>
<script>
var numbers = [4, 9, 16, 25];
function myFunction() {
x = document.getElementById("demo")
x.innerHTML = numbers.map(Math.sqrt);
}
</script>
</body>
</html>
this code is going to output 2,3,4,5
but can you make it output 2,4 so it checks the first value in the array then skips the second until the end
or
3,5 so it skips the first value in the array then checks the second value.
is this possible using the map method? or do I have to use a for loop?
Share Improve this question asked Nov 6, 2018 at 18:37 ylimesylimes 771 gold badge3 silver badges10 bronze badges 1- 1 Possible duplicate of How to skip over an element in .map()? – ssc-hrep3 Commented Nov 6, 2018 at 18:43
2 Answers
Reset to default 2You can use .filter() on the mapped array:
let numbers = [4, 9, 16, 25];
let output1 = numbers.map(Math.sqrt).filter((_, i) => (i % 2 == 0));
let output2 = numbers.map(Math.sqrt).filter((_, i) => (i % 2 != 0));
console.log(output1);
console.log(output2);Is not possible using the function map because this function creates a new array with the same length of the source array.
An alternative is using the function reduce.
var numbers = [4, 9, 16, 25];
var result = numbers.reduce((a, n, i) => {
if (n % 2 === 0) a.push(Math.sqrt(n));
return a;
}, []);
console.log(result);