This is frustrating, I want to simply create new input field inside div on my aspx page when button is clicked. I use javascript function witch appends new child element(input field) to existing div. It all looks like this:
<%@ Page Language="C#" AutoEventWireup="true" CodeFile="test.aspx.cs" Inherits="Pages_test" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" ".dtd">
<html xmlns="">
<head runat="server">
<title></title>
<script type="text/javascript">
function clone() {
var html = document.createElement("input");
html.setAttribute("id", 1);
html.setAttribute("name", "dejan");
html.setAttribute("value", "some text");
html.setAttribute("type", "text");
document.getElementById("panj").appendChild(html);
}
</script>
</head>
<body>
<form id="form1" runat="server">
<div id="panj">
Djubrov
</div>
<asp:Button ID="Button1" runat="server" Text="Button" OnClientClick="clone()" />
</form>
</body>
</html>
Funny thing is that text element with set text value flashes for second when i click the button but it disappears afterwords. Do I missing something?
This is frustrating, I want to simply create new input field inside div on my aspx page when button is clicked. I use javascript function witch appends new child element(input field) to existing div. It all looks like this:
<%@ Page Language="C#" AutoEventWireup="true" CodeFile="test.aspx.cs" Inherits="Pages_test" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3/1999/xhtml">
<head runat="server">
<title></title>
<script type="text/javascript">
function clone() {
var html = document.createElement("input");
html.setAttribute("id", 1);
html.setAttribute("name", "dejan");
html.setAttribute("value", "some text");
html.setAttribute("type", "text");
document.getElementById("panj").appendChild(html);
}
</script>
</head>
<body>
<form id="form1" runat="server">
<div id="panj">
Djubrov
</div>
<asp:Button ID="Button1" runat="server" Text="Button" OnClientClick="clone()" />
</form>
</body>
</html>
Funny thing is that text element with set text value flashes for second when i click the button but it disappears afterwords. Do I missing something?
Share Improve this question asked Feb 22, 2012 at 23:24 Dejan StuparicDejan Stuparic 5952 gold badges15 silver badges32 bronze badges 2- 1 Why do you think that elements that are created on clientside remain after postbacks? The server does not even know that they exist and will not recreate them. – Tim Schmelter Commented Feb 22, 2012 at 23:32
- How do i then create new element when some user-inflicted-event fires, and make them visible on same page? – Dejan Stuparic Commented Feb 22, 2012 at 23:36
3 Answers
Reset to default 7Every time you click that button it will cause a postback.
Fix it by stoping postback as follows:
<asp:Button ID="Button1" runat="server" Text="Button" OnClientClick="clone(); return false;" />
Your button engenders a request to the server, and the ensuing response is overwriting the page with a new HTML document. Return false from the JavaScript function to prevent the asp:Button postback:
function clone() {
// your above code
return false;
}
and modify the button like
OnClientClick="return clone()"
If your asp:Button does not require interaction with the server, consider making it a <button> or <input type='button' />.
If you need the value from this generated text field in code behind, you would be much better off not to create it dynamically via Javascript. You could just create a normal textbox and set it to be initially invisible like so:
<asp:TextBox ID="yourTextboxID" Visible="False" runat="server" />
When the button is pressed, handle the event in the code behind and make the textbox visible:
yourTextboxID.Visible = True;
Viewstate will keep the values across postbacks.
If each button press should create an additional textbox, you could also do this in the codebehind, i.e. use a placeholder in the ascx and then attach a new textbox to it with each button press:
yourPlaceholderID.Controls.Add(new TextBox() { ID = "textbox1" });