I have an array of arrays like below.

array = [[false, 1, "label", "label value", null],[false, 2, "label1", "label1", null]]

I want to find the row matching to checkNum and return that row. checkNum is pared to the second index element. I don't want to put a for loop something like below,

checkNum = 1;
for (let i = 0; i < array.length; i++) {
  if ((array[i][1]) === checkNum) {
  }
}

I have an array of arrays like below.

array = [[false, 1, "label", "label value", null],[false, 2, "label1", "label1", null]]

I want to find the row matching to checkNum and return that row. checkNum is pared to the second index element. I don't want to put a for loop something like below,

checkNum = 1;
for (let i = 0; i < array.length; i++) {
  if ((array[i][1]) === checkNum) {
  }
}

• javascript
• arrays

• do you have only one item in the array which match, or could there be more? – Nina Scholz Commented Apr 26, 2019 at 16:10
• array.filter((row) => row[1] === checkNum)[0] – karthick Commented Apr 26, 2019 at 16:11

2 Answers 2

Use Array.filter() to get an array of items that match the criteria, or Array.find() the get the 1st item that matches.

const array = [[false, 1, "label", "label value", null],[false, 2, "label1", "label1", null]]
const checkNum = 1

console.log(array.filter(({ 1: n }) => n === checkNum)) // array of items
console.log(array.find(({ 1: n }) => n === checkNum)) // 1st item found

You could find the item with Array#find.

var array = [[false, 1, "label", "label value", null], [false, 2, "label1", "label1", null]],
    checkNum = 1,
    result = array.find(a => a[1] === checkNum);

console.log(result);