I have an array that looks like this

   const array: any[] = []
   array.push({ 'Comments': thisment, 'Name': this.name, 'Description' : this.description })

I pass that array back to a parent ponent. How can I grab the value that is in Comments?

I have an array that looks like this

   const array: any[] = []
   array.push({ 'Comments': this.ment, 'Name': this.name, 'Description' : this.description })

I pass that array back to a parent ponent. How can I grab the value that is in Comments?

• javascript

• What have you tried, how did it not work? Or do you just not know the basic access operations? – Bergi Commented Sep 30, 2017 at 15:31
• 3 This has nothing to do with TypeScript nor AngularJS. – Andreas Commented Sep 30, 2017 at 15:31
• Suggest changing the title to remove 'typescript' – isimmons Commented Jan 11, 2023 at 5:04

4 Answers 4

You can use forEach loop :

const mentArray = [];
array.forEach(function(object) {
    var ment = object.Comments;
    mentArray.push(ment);
});
//You can store all ments in another array and use it...
console.log("This is ment array...", mentArray);

Or use map but it will work in new browsers possibly ones following ES6:

const mentArray = array.map(function(object) {
    return object.Comments;
});
console.log("This is ment array... ", mentArray);

As long as TGW's answer is "correct" and works, I think you should be aware of and use for...of (and for...in) construction, it's superior over Array.forEach (faster, you can use continue and break keywords, better readability) and more often you want to iterate over your array and do things with it, than just get one property (which Array.map is perfect for in this case :) )

You may try for this:

We can also use filter here.

let mentArray:any[];
array.filter(function(object) {
    var ment = object.Comments;
    mentArray.push(ment);
});
//Store here and use this.
console.log("This is ment array...", mentArray);

You can use Underscore JS for short and better performance like below:

    let ids: Array<number> = _.map(this.mylist, (listObj) => {
        return listObj.Id;
    });