Existing Url

.php?id=1&branch_id=4&course_id=5

New url

.php?id=1&branch_id=4

removing course_id from existing url

How to remove one parameter value from url.

Tried below code:

function replaceUrlParam(url, paramName, paramValue){
    var pattern = new RegExp('(\\?|\\&)('+paramName+'=).*?(&|$)')
    var newUrl=url
    if(url.search(pattern)>=0){
        newUrl = url.replace(pattern,'$1$2' + paramValue + '$3');
    }
    else{
        newUrl = newUrl + (newUrl.indexOf('?')>0 ? '&' : '?') + paramName + '=' + paramValue
    }
    return newUrl
}

but its not working...

Existing Url

http://example./home.php?id=1&branch_id=4&course_id=5

New url

http://example./home.php?id=1&branch_id=4

removing course_id from existing url

How to remove one parameter value from url.

Tried below code:

function replaceUrlParam(url, paramName, paramValue){
    var pattern = new RegExp('(\\?|\\&)('+paramName+'=).*?(&|$)')
    var newUrl=url
    if(url.search(pattern)>=0){
        newUrl = url.replace(pattern,'$1$2' + paramValue + '$3');
    }
    else{
        newUrl = newUrl + (newUrl.indexOf('?')>0 ? '&' : '?') + paramName + '=' + paramValue
    }
    return newUrl
}

but its not working...

• javascript
• jquery

• 2 .replace(/[&?]course_id=\d+/, '') – Tushar Commented Apr 24, 2017 at 10:45
• jsfiddle/fc0q69dd – John R Commented Apr 24, 2017 at 10:50

2 Answers 2

As you said that you want to use variable instead of directly using .replace(/&course_id=\d+/, ''), you can do it like below:-

Example:-

var re = new RegExp("&course_id=\\d+");
var newUrl="http://example./home.php?id=1&branch_id=4&course_id=5";
console.log(newUrl.replace(re, ''));

<script src="https://ajax.googleapis./ajax/libs/jquery/2.1.1/jquery.min.js"></script>

You can simply do that by using this code to remove &course_id=5:

var url = "http://example./home.php?id=1&branch_id=4&course_id=5";
url.replace(/([&\?]course_id=5*$|course_id=5&|[?&]course_id=5(?=#))/, '');

It will return you: http://example./home.php?id=1&branch_id=4