I have this code
function verifyKey(e)
{
var keycode;
if (window.event)
keycode = window.event.keyCode;
else if (e)
keycode = e.which;
regex=/[1-9]/;
if(regex.test(keycode))
return true;
else
void(0);
}
in the html I added an input and I add the onkeydown event onkeydown="verifyKey(event);"
I like to verify the key before it display on the text
If the key is a number or a(,) or full stop(.) then accept the key else refuse it
Thanks
I have this code
function verifyKey(e)
{
var keycode;
if (window.event)
keycode = window.event.keyCode;
else if (e)
keycode = e.which;
regex=/[1-9]/;
if(regex.test(keycode))
return true;
else
void(0);
}
in the html I added an input and I add the onkeydown event onkeydown="verifyKey(event);"
I like to verify the key before it display on the text
If the key is a number or a(,) or full stop(.) then accept the key else refuse it
Thanks
Share Improve this question edited Sep 26, 2011 at 12:38 Pointy 414k62 gold badges595 silver badges629 bronze badges asked Sep 26, 2011 at 12:35 RadRad 4,9414 gold badges27 silver badges28 bronze badges 01 Answer
Reset to default 7Here in your code you are testing the regular expression defined with the keycode, so every chearactes on the keyboard will be allowed since the keycode of every key is numbers, so you will not get the result what you expect. Instead of using the regular expression try the below code
<html>
<head>
<script type="text/javascript">
function verifyKey(e)
{
var keycode;
if (window.event)
keycode = window.event.keyCode;
else if (e)
keycode = e.which;
if((keycode>=48 && keycode<=57))
{alert("if")
return true;
}
else if((keycode == 188)||(keycode == 190))
{alert("elseif");
return true;
}
else
{alert("else")
return false;
}
}
</script>
</head>
<body>
<input type="text" onkeypress="return verifyKey(event)" />
</body>
</html>