My airbnb styleguide told me I should use Array Destructuring for the assignment below.

const splittedArr  = [1, 2, 3, 4, 5]
const result = splittedArr[1];

So I wrote it like this using skipping values , to get the second element.

const splittedArr  = [1, 2, 3, 4, 5]
const [, result] = splittedArr;

const splittedArr = [1, 2, 3, 4, 5]
const result = splittedArr[1];

const [, res] = splittedArr;

console.log(result, res);

My airbnb styleguide told me I should use Array Destructuring for the assignment below.

const splittedArr  = [1, 2, 3, 4, 5]
const result = splittedArr[1];

So I wrote it like this using skipping values , to get the second element.

const splittedArr  = [1, 2, 3, 4, 5]
const [, result] = splittedArr;

const splittedArr = [1, 2, 3, 4, 5]
const result = splittedArr[1];

const [, res] = splittedArr;

console.log(result, res);

But for instance when I have a higher indice to destruct

const splittedArr  = [1, 2, 3, 4, 5]
const result = splittedArr[5];

This would mean I have to write it like

const splittedArr  = [1, 2, 3, 4, 5]
const [,,,, result] = splittedArr;

const splittedArr  = [1, 2, 3, 4, 5]

const result = splittedArr[4];

const [, , , , res] = splittedArr;

console.log(result, res);

Question: Is there a better way to write Array Destructuring with skipping values in JavaScript?

• javascript
• arrays
• destructuring
• airbnb-js-styleguide

• That's a guideline not a fixed rule. Have a look at the issues for that part of the guide (e.g. Why use prefer-destructuring on arrays? #1791) – Andreas Commented Jan 30, 2021 at 10:56
• 1 Please use mon sense. It's far uglier to do [,,,,,myvar] = ar than const myvar = ar[5] and any style guide that tells you otherwise is wrong. – 404 Commented Jan 30, 2021 at 16:37
• 1 Does this answer your question? Object destructuring solution for long arrays? – Nguyễn Văn Phong Commented Jan 31, 2021 at 4:25
• My question is about Array Destructuring and not Object destructuring as you can see in my title and the title of your prodivded question. – Aalexander Commented Jan 31, 2021 at 7:36

2 Answers 2

You could treat the array as object and destructure with the index as key and assign to a new variable name.

const
    array = [37, 38, 39, 40, 41, 42, 43],
    { 5: result } = array;

console.log(result);

Use object-destructuring instead:

const splittedArr  = [1, 2, 3, 4, 5];

const { 1: second, 4: fifth } = splittedArr;

console.log(second, fifth);