What I am trying is to match until first occurrence of & met. Right now it is matching only the last occurrence of &.
My regular expression is
(?!^)(http[^\\]+)\&
And I'm trying to match against this text:
;sa3Dt&url3D;ct3Dga&cd3DCAEYACoTOTEwNTAyMzI0OTkyNzU0OTI0MjIaMTBmYTYxYzBmZDFlN2RlZjpjb206ZW46VVM&usg3DAFQjCNE6oIhIxR6qRMBmLkHOJTKLvamLFg
What I need is:
Click for the codebase.
What I am trying is to match until first occurrence of & met. Right now it is matching only the last occurrence of &.
My regular expression is
(?!^)(http[^\\]+)\&
And I'm trying to match against this text:
https://www.google./url?rct3Dj&sa3Dt&url3Dhttp://business.itbusinessnet./article/WorldStage-Supports-Massive-4K-Video-Mapping-at-Adobe-MAX-with-Christie-Boxer-4K-Projectors---4820052&ct3Dga&cd3DCAEYACoTOTEwNTAyMzI0OTkyNzU0OTI0MjIaMTBmYTYxYzBmZDFlN2RlZjpjb206ZW46VVM&usg3DAFQjCNE6oIhIxR6qRMBmLkHOJTKLvamLFg
What I need is:
http://business.itbusinessnet./article/WorldStage-Supports-Massive-4K-Video-Mapping-at-Adobe-MAX-with-Christie-Boxer-4K-Projectors---4820052
Click for the codebase.
Share Improve this question edited Feb 21, 2017 at 0:50 apsillers 116k18 gold badges247 silver badges247 bronze badges asked Feb 21, 2017 at 0:44 AmazingDayTodayAmazingDayToday 4,28215 gold badges41 silver badges70 bronze badges1 Answer
Reset to default 12Use the non-greedy mode like this:
/(?!^)(http[^\\]+?)&/
// ^
In non-greedy mode (or lazy mode) the match will be as short as possible.
If you want to get rid ot the & then just wrap it in a lookahead group so it won't be in the match like this:
/(?!^)(http[^\\]+?)(?=&)/
// ^^ ^
Or you could optimize the regular expression as @apsillers suggested in the ment bellow like this:
/(?!^)(http[^\\&]+)/
Note: & is not a special character so you don't need to escape it,