I have this code to replace all opening and closing square brackets which has a matching variable inside:

for (var j = 0; j <= temp.length; j++) {
    var re = new RegExp("["+j+"]", 'g');
    imgData = imgData.replace(re, temp[j]);
}

The line var re = new RegExp("["+j+"]", 'g'); doesn't work because I assume the brackets aren't being escaped. Does anyone know how I would escape them, but still be able to have a variable in the pattern? Thanks! :)

I have this code to replace all opening and closing square brackets which has a matching variable inside:

for (var j = 0; j <= temp.length; j++) {
    var re = new RegExp("["+j+"]", 'g');
    imgData = imgData.replace(re, temp[j]);
}

The line var re = new RegExp("["+j+"]", 'g'); doesn't work because I assume the brackets aren't being escaped. Does anyone know how I would escape them, but still be able to have a variable in the pattern? Thanks! :)

• javascript
• regex
• replace

1 Answer 1

You should escape it with backslashes:

var re = new RegExp("\\[" + j + "\\]", "g");