So i have to validate the gpa being entered so that it follows the guidelines first number is 0-4 the next thing is a (.) followed by 2 more digits 0-9. This is what i have but it is not working.

function validateGPA(gpa){
        var errorValue = gpa;
        var legalValue = /^\[0-4]\[.]\d\d$/;
        console.log(gpa);
        if(gpa == ""){
            errorValue = "Please enter your GPA.\n";
        }   else if(!legalValue.test(gpa)){
            errorValue = "Please enter a 3 digit gpa.\n";
        }
        return errorValue;
    }

Im not sure what im doing wrong, Ive tried a few tweaks but nothing seems to be working.

So i have to validate the gpa being entered so that it follows the guidelines first number is 0-4 the next thing is a (.) followed by 2 more digits 0-9. This is what i have but it is not working.

function validateGPA(gpa){
        var errorValue = gpa;
        var legalValue = /^\[0-4]\[.]\d\d$/;
        console.log(gpa);
        if(gpa == ""){
            errorValue = "Please enter your GPA.\n";
        }   else if(!legalValue.test(gpa)){
            errorValue = "Please enter a 3 digit gpa.\n";
        }
        return errorValue;
    }

Im not sure what im doing wrong, Ive tried a few tweaks but nothing seems to be working.

• javascript
• regex

• Why are you escaping [? – user663031 Commented Nov 14, 2014 at 1:30

3 Answers 3

This is the shortest expression:

/^[0-4]\.\d\d$/

Explanation:

^     - Start of line
[0-4] - One digit in the range 0-4
\.    - A dot, which needs to be escaped with a backslash.
        Without the backslash it means "any character apart from line break"
\d\d  - Two digits (any value from 0-9)
$     - End of line

Try like this:

/^[0-4]\.\d{2}$/

/^[0-4][.][0-9][0-9]$/

^ matches all strings starting with a number between 0 and 4 $ - Means the string ends with a number from 0 to 9

Hope this helps.