I have to get filename of the uploaded file and set it to the textfield

I have done as follows

<input type="file" name = "filename" id="upload">
<input type="text" name = "file" id="file">

//jquery

$('#upload').change(function() {
    var filename = $('input[type=file]').val().split('\\').pop();
    var lastIndex = filename.lastIndexOf("\\");
    $('#file').val(filename);
});

and also tried this

$('#upload').change(function() {
    var filename = $(this).val();
    var lastIndex = filename.lastIndexOf("\\");
    if (lastIndex >= 0) {
        filename = filename.substring(lastIndex + 1);
    }
    $('#file').val(filename);
});

but filename is not displayed in the textfield.

I have to get filename of the uploaded file and set it to the textfield

I have done as follows

<input type="file" name = "filename" id="upload">
<input type="text" name = "file" id="file">

//jquery

$('#upload').change(function() {
    var filename = $('input[type=file]').val().split('\\').pop();
    var lastIndex = filename.lastIndexOf("\\");
    $('#file').val(filename);
});

and also tried this

$('#upload').change(function() {
    var filename = $(this).val();
    var lastIndex = filename.lastIndexOf("\\");
    if (lastIndex >= 0) {
        filename = filename.substring(lastIndex + 1);
    }
    $('#file').val(filename);
});

but filename is not displayed in the textfield.

• javascript
• jquery
• html
• file
• jsp

• 1 What do you mean by not working? – Perdomoff Commented Jan 7, 2016 at 15:37
• filename is not displayed in the textfield – Rohin Commented Jan 7, 2016 at 15:51
• 1 works fine for me jsbin./yuyuriqevi/1/edit?html,js,output – tkay Commented Jan 7, 2016 at 15:58
• but not for me. Is there is anything wrong? – Rohin Commented Jan 7, 2016 at 16:01
• @Rohin check my answer. – tkay Commented Jan 7, 2016 at 16:05

1 Answer 1

You are supposed to be using jquery inside document ready. You might have forgotten to add that. Here is the working code.

      $(document).ready(function() {

    $('#upload').change(function() {
       var filename = $('input[type=file]').val().split('\\').pop();
      console.log(filename,$('#file'));
        var lastIndex = filename.lastIndexOf("\\");   
        $('#file').val(filename);
    });
      });

<script src="https://ajax.googleapis./ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<input type="file" name = "filename" id="upload">
                                <input type="text" name = "file" id="file">