I have prepared a JSON data and I need to post it on the server so that a service can be called. URL to the server is available and I am making an AJAX call for the same to POST the data.
But I dont know where to place the JSON string that is generated.
My Code is as Follows:
function postJSONData(JSONData, localMode)
{
var localJSONData = JSONData;
var postMode = localMode;
$.ajax({
type: 'POST',
url: '',
dataType: 'xml',
success: function(data){
alert("SECOND POST JSON DATA");
} // Success Function
}); // AJAX Call
alert("POST JSON ------------> "+localJSONData +" "+postMode);
}
I want to post JSON data to the server URL. any Parameters to be used?
Thanks, Ankit.
I have prepared a JSON data and I need to post it on the server so that a service can be called. URL to the server is available and I am making an AJAX call for the same to POST the data.
But I dont know where to place the JSON string that is generated.
My Code is as Follows:
function postJSONData(JSONData, localMode)
{
var localJSONData = JSONData;
var postMode = localMode;
$.ajax({
type: 'POST',
url: 'https://tt.s2./tmobile/subscribe-service/uid=ankit_bharat_tanna',
dataType: 'xml',
success: function(data){
alert("SECOND POST JSON DATA");
} // Success Function
}); // AJAX Call
alert("POST JSON ------------> "+localJSONData +" "+postMode);
}
I want to post JSON data to the server URL. any Parameters to be used?
Thanks, Ankit.
Share Improve this question edited Jan 9, 2013 at 7:37 Ankit Tanna asked Jan 9, 2013 at 7:35 Ankit TannaAnkit Tanna 1,8198 gold badges34 silver badges63 bronze badges 6-
1
data : { "requestParamName" : localJSONData }
where"requestParamName"
is whatever parameter name you are using in your server-side code to receive the JSON. – nnnnnn Commented Jan 9, 2013 at 7:39 - Please visit the jQuery .ajax() doc and scroll down to read about the data setting. – PhearOfRayne Commented Jan 9, 2013 at 7:42
-
why
dataType:'xml'
you want to send it xml based or you want to access it? – Jai Commented Jan 9, 2013 at 7:44 - I want to sent JSON data to the server. – Ankit Tanna Commented Jan 9, 2013 at 7:49
- what is your variable localJSONData cantains , please show us – Kanishka Panamaldeniya Commented Jan 9, 2013 at 8:00
2 Answers
Reset to default 2You should pass the values with data parameter $.ajax() jquery doc link
function postJSONData(JSONData, localMode)
{
var localJSONData = JSONData;
var postMode = localMode;
$.ajax({
type: 'POST',
url: 'https://tt.s2./tmobile/subscribe-service/uid=ankit_bharat_tanna',
contentType:"application/json; charset=utf-8",
dataType:"json"
data: JSONData
success: function(data){
alert("SECOND POST JSON DATA");
} // Success Function
}); // AJAX Call
alert("POST JSON ------------> "+localJSONData +" "+postMode);
}
You are missing the data
parameter. Moreover you need to send json
data so dataType
parameter should be set to json
. Below is an Example
function postJSONData(JSONData, localMode)
{
var localJSONData = JSONData;
var postMode = localMode;
$.ajax({
data: localJSONData,
type: 'POST',
url: 'https://tt.s2./tmobile/subscribe-service/uid=ankit_bharat_tanna',
dataType: 'json',
success: function(data){
alert("SECOND POST JSON DATA");
} // Success Function
}); // AJAX Call
alert("POST JSON ------------> "+localJSONData +" "+postMode);
}