This bookmarklet is working as expected.

javascript:{window.location='='+encodeURIComponent(window.location.href)}

But it sends the entire URL to bing. Instead I need only the last part to be sent. For e.g. If I am on the page

.aspx

Then it should send only "aa286483.aspx" to bing. Is this possible?

This bookmarklet is working as expected.

javascript:{window.location='http://bing./search?q='+encodeURIComponent(window.location.href)}

But it sends the entire URL to bing. Instead I need only the last part to be sent. For e.g. If I am on the page

https://msdn.microsoft./en-us/library/aa286483.aspx

Then it should send only "aa286483.aspx" to bing. Is this possible?

• javascript
• bookmarklet

4 Answers 4

function getFileName(url) {
  return url.split("/").pop();
}
var url = "https://msdn.microsoft./en-us/library/aa286483.aspx";
console.log(getFileName(url));

And note that you should take care of url parameters (aa286483.aspx/?id=2 for example) too if it is important in your case. I don't include it here since your question is about file name only.

There is window.location.pathname, which will return /en-us/library/aa286483.aspx.

A direct approach it will be:

window.location.pathname.split('/').slice(-1)[0]

Just read past the last path delimiter?

var url  = window.location.pathname;
var last = url.substr(url.lastIndexOf("/") + 1);

you can do:

var array = window.location.href.split('/'),
     res = "";

 while(res === "") {
   res = array.pop();
 }

 return res;

this will prevent you from returning an empty string if the URL ends with '/'