I need to find the shortest code for reversing an array and at the moment I have this:
weirdReverse=a=>a.sort(()=>1)
This is a codewars challenge and the length of this is 29 bytes. I need to have a length <=28 so I need to remove 1 byte and I can't change this part:
weirdReverse=a=>a
And I can't use reverse()
.
I need to find the shortest code for reversing an array and at the moment I have this:
weirdReverse=a=>a.sort(()=>1)
This is a codewars challenge and the length of this is 29 bytes. I need to have a length <=28 so I need to remove 1 byte and I can't change this part:
weirdReverse=a=>a
And I can't use reverse()
.
-
1
How is sort order determined, here? Couldn't you just leave out the
()=>1
? – Daedalus Commented May 22, 2018 at 22:11 - Sorry im dumb , i need to reverse it i just look on sort() and i write i need to sort it , description is changed now – Mariusz Commented May 22, 2018 at 22:13
-
3
array.reverse()
.. am I missing something?? – mhodges Commented May 22, 2018 at 22:14 - didnt write it too ... i can't use reverse() – Mariusz Commented May 22, 2018 at 22:15
2 Answers
Reset to default 9You can golf one byte off your anonymous arrow function by specifying an unused parameter instead of ()
to indicate no named parameters, bringing the total down to 28 bytes:
weirdReverse=a=>a.sort(_=>1)
You can use a named parameter instead of braces, like so:
weirdReverse=a=>a.sort(b=>1)