I'm suggested to use JQuery data table. Now I need to populate grid with bunch of json objects sent from my controller. How can I send this data on the grid from js

$.ajax({
            ...
            url: '/Home/ReturnJsonData',
            success: function (result) {
                $.each(result, function (i, item) {
                    // this is where I should sent item object to my grid
                });
            },

            error: function () { alert("error"); }
        });

Update I've found these link, but I dont know how to implement it.

I'm suggested to use JQuery data table. Now I need to populate grid with bunch of json objects sent from my controller. How can I send this data on the grid from js

$.ajax({
            ...
            url: '/Home/ReturnJsonData',
            success: function (result) {
                $.each(result, function (i, item) {
                    // this is where I should sent item object to my grid
                });
            },

            error: function () { alert("error"); }
        });

Update I've found these link, but I dont know how to implement it.

• javascript
• jquery
• json

• So why don't you parse the result, and create a table element then push the result's elements as rows, finally activate jQuery DataTable ? – Issa Qandil Commented Sep 12, 2012 at 8:40
• @IssaQandil can you show me on concrete example ? – panjo Commented Sep 12, 2012 at 8:51

4 Answers 4

You should use JQuery DataTable sAjaxSource property to specify ajaxsource in your case it would be /HomeReturnJsonData

An example follow

$(document).ready(function () {

 $('#myDataTable').dataTable({
    "bServerSide": true,
    "sAjaxSource": "Home/ReturnJsonData",
    "bProcessing": true,
    "aoColumns": [
                    { "sName": "ID",
                        "bSearchable": false,
                        "bSortable": false,
                        "fnRender": function (oObj) {
                            return '<a href=\"Details/' + 
                            oObj.aData[0] + '\">View</a>';
                        }
                    },
                    { "sName": "COMPANY_NAME" },
                    { "sName": "ADDRESS" },
                    { "sName": "TOWN" }
                ]
 });
}); 

You can use Jquery Grid Plugin in that case.

Read this article to use MVC Data Grid: using jqGrid and JSON

http://blog.davidrenz./?p=663

Update:

In that case if you only want to use J-query Datatable go to this link.

http://www.codeproject./Articles/155422/jQuery-DataTables-and-ASP-NET-MVC-Integration-Part

I put this in a function because that was the easiest way to do it for me, feel free to copy the function and use it. All your going to need to change is the url and the column names and number there of. To call it just copy the html with the paths done so that they match whatever yours are.

function SetUpGrid(tableID, pagerID, data) {
    $("#" + tableID).jqGrid({
        url: '/pagename/stuff?data=' + data,
        datatype: 'json',
        mtype: 'GET',
        colNames: ['col name1', 'col name2', ... 'col nameN'],
        colModel: [
      { name: 'colName1', index: 'colName1', align: "center", sortable: true, editable: false, resizable: false },
      { name: 'colName2', index: 'colName2', align: "center", sortable: true, editable: false, resizable: false },
      ...
      { name: 'colNameN', index: 'colNameN', align: "center", sortable: true, editable: false, resizable: false }
    ],
    pager: '#' + pagerID,
    autowidth: true,
    viewrecords: true,
    rowNum: 15,
    pgbuttons: true,
    pginput: false,
    pgtext: "Page {0} of {1}",
    recordtext: "Data {0} - {1} of {2}",
    emptyrecords: "No data to display",
    loadui: true,
    rowList: [15, 30, 60],
    scrollrows: true,
    hidegrid: true,
    sortorder: "desc",
    beforeRequest: function () { // This just inserts a loading image, you don't need it but I was loading a lot of data and wanted the user to know something was happening.
        $("#" + tableID).empty().append('<tr><td><img src="/Content/imgs/loading.gif" /></td></tr>');
    },
    loadComplete: function (data) {
        /*
        Called when the json load is done, this is a way to insert the data the way I want to.
        Feel free to use whatever you want like links or <p>s or <div>s or whatever.
        */
        if (data.length > 1) {
            for (var key in data) {
                if (data.hasOwnProperty(key)) {
                    $("#" + tableID).empty().append("<tr><td>" + data[key].colName1 + "</td><td>" + data[key].colName12+ "</td> ... <td>" + data[key].colNameN + "</td></tr>");
                }
            }
        } else {
            $("#" + tableID).empty().append("<tr><td>" + this.colName1 + "</td><td>" + this.colName2 + "</td> ... <td>" + this.colNameN + "</td></tr>");
        }
    },
    loadError: function (xhr, status, error) {
        // Called when an error occurs, handle as you wish, if you even do.
        alert(xhr);
        alert(status);
        alert(error);
    }
});
$("#" + tableID).jqGrid("navGrid", "#" + pagerID, { add: false, edit: false, refresh: false, del: false, search: false }).trigger("reloadGrid", [{ page: 1 }]);
}

<script src="/Scripts/jquery-1.7.2.js"></script>
<script src="/Scripts/jquery-ui-1.8.23.min.js"></script>
<script src="/Scripts/jquery.jqGrid.min.js"></script>
<script src="/Scripts/grid.locale-en.js"></script>
<script src="/Scripts/ADTFunding.js"></script>
<link href="/Content/themes/base/jquery.ui.all.css" rel="stylesheet" type="text/css" />
<link href="/Content/jquery.jqGrid/ui.jqgrid.css" rel="stylesheet" type="text/css" />
<script type="text/javascript">
    $(function () {
        SetUpFundingGrid('dataTable', 'pager', '9895998');
    });
</script>
<table id="dataTable"></table>
<div id="pager"></div>

You can also use the fnAddData property to push json to table. Check this article https://jqueryajaxphp./jquery-datatable-using-json/