I have a form created in a Google Apps spreadsheet and I am trying to find out some of the forms parameter data in my script.
In the following code I don't understand why I am getting an 'Invalid argument' error at the line
var myForm = FormApp.openByUrl(formURL);
even though the log shows what I think is a valid formURL
string.
function myFunction() {
var ss = SpreadsheetApp.getActive();
var formURL = ss.getGetFormURL();
Logger.log('Spreadsheet\'s formURL: %s', formURL);
var myForm = FormApp.openByUrl(formURL); // Google script shows the ERROR here
Logger.log('Form PublishedURL: %s', myForm.getPublishedUrl());
}
I have a form created in a Google Apps spreadsheet and I am trying to find out some of the forms parameter data in my script.
In the following code I don't understand why I am getting an 'Invalid argument' error at the line
var myForm = FormApp.openByUrl(formURL);
even though the log shows what I think is a valid formURL
string.
function myFunction() {
var ss = SpreadsheetApp.getActive();
var formURL = ss.getGetFormURL();
Logger.log('Spreadsheet\'s formURL: %s', formURL);
var myForm = FormApp.openByUrl(formURL); // Google script shows the ERROR here
Logger.log('Form PublishedURL: %s', myForm.getPublishedUrl());
}
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edited Jun 26, 2020 at 20:45
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asked May 24, 2013 at 22:45
user2419137user2419137
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- report issues/bugs here code.google./p/google-apps-script-issues/issues/list – eddyparkinson Commented May 27, 2013 at 13:49
-
1
Documentation says
openByUrl()
"Throws an exception if the URL is invalid or the user does not have permission to open the form." Did you check that permissions were set appropriately? – Mogsdad Commented May 27, 2013 at 15:56
2 Answers
Reset to default 4Try opening the form using its ID rather than the URL. You can find the ID of the form from its URL.
var myForm = FormApp.openById(id)
openById and openByUrl only works with the NEW forms service. So if form was created with old service, it won't work. See:
http://code.google./p/google-apps-script-issues/issues/detail?id=2866