I have the following:

function showUnicode()
{
  var text = prompt( 'Enter the wanted text', 'Unicode' ),
      unicode = 0,
      ntext,
      temp,
      i = 0
  ;

  // got the text now transform it in unicode
  for(i; i < text.length; i++)
  {
    unicode += text.charCodeAt(i)

  }

  // now do an alert
  alert( 'Here is the unicode:\n' + unicode + '\nof:\n' + text )

}

Thanks for the idea to initialize unicode but now unicode variable gets the Unicode of the last character, why does it?

I have the following:

function showUnicode()
{
  var text = prompt( 'Enter the wanted text', 'Unicode' ),
      unicode = 0,
      ntext,
      temp,
      i = 0
  ;

  // got the text now transform it in unicode
  for(i; i < text.length; i++)
  {
    unicode += text.charCodeAt(i)

  }

  // now do an alert
  alert( 'Here is the unicode:\n' + unicode + '\nof:\n' + text )

}

Thanks for the idea to initialize unicode but now unicode variable gets the Unicode of the last character, why does it?

• javascript
• unicode

• 2 unicode is not initialized, so it is undefined. In the first iteration, you are basically doing undefined + someNumber and undefined is converted to NaN. – Felix Kling Commented Jan 18, 2012 at 18:57
• charCodeAt returns an integer repsenting the unicode codepoint value. If you add them up as you are, you'll be getting back the equivalent of "1+2+3=6", not "123". – Marc B Commented Jan 18, 2012 at 18:58
• No need to mask your JavaScript block: <!-- --> – Diodeus - James MacFarlane Commented Jan 18, 2012 at 18:58
• 2 A good practice - ending each statement with a semicolon. – Grace Huang Commented Jan 18, 2012 at 18:58
• well now i initialized unicode to 0 but it shows just the unicode of the last character – Andrew Commented Jan 18, 2012 at 19:08

3 Answers 3

JavaScript uses UCS-2 internally.

This means that supplementary Unicode symbols are exposed as two separate code units (the surrogate halves). For example, '