I have a table to which i dynamically add rows. The number of days is equal to the date difference of the dates inserted by user. On the dynamic rows i want to add three fields. The first two are date and day filed. For that I need to know the next date and the corresponding day. For example user enters 10-2-2012. I need to insert The next dates like 17-2-2012,18-2-2012... and corresponding days like Wednesday, Thursday..etc I have used the following function to get next date

function getTomorrow(d,offset)
{
    if (!offset)
    {
       offset = 1
    }
    return new Date(new Date().setDate(d.getDate() + offset));
}

But it shows error 16-2-2012 has no getDate() function. Am not able to find next date and the corresponding day. Is there any way to get it?

I have a table to which i dynamically add rows. The number of days is equal to the date difference of the dates inserted by user. On the dynamic rows i want to add three fields. The first two are date and day filed. For that I need to know the next date and the corresponding day. For example user enters 10-2-2012. I need to insert The next dates like 17-2-2012,18-2-2012... and corresponding days like Wednesday, Thursday..etc I have used the following function to get next date

function getTomorrow(d,offset)
{
    if (!offset)
    {
       offset = 1
    }
    return new Date(new Date().setDate(d.getDate() + offset));
}

But it shows error 16-2-2012 has no getDate() function. Am not able to find next date and the corresponding day. Is there any way to get it?

• javascript
• jquery

• 1 Please provide a demonstration of your problem. What is d? How do you call getTomorrow? – Zeta Commented Feb 16, 2012 at 8:36
• d is the date in dd-mm-yy format – user1199657 Commented Feb 16, 2012 at 8:38
• In case you find yourself doing a lot of date manipulation in the future, I can't remend moment.js enough. Adding days to an existing date is just a matter of moment().add('d', 1);. – geca Commented Feb 16, 2012 at 8:52

3 Answers 3

You have to convert the string d into a Date object:

function getTomorrow(d,offset){
    if (!offset){
        offset = 1;
    }
    if(typeof(d) === "string"){
        var t = d.split("-"); /* splits dd-mm-year */
        d = new Date(t[2],t[1] - 1, t[0]);
    //  d = new Date(t[2],t[1] - 1, t[0] + 2000); /* for dd-mm-yy */
    }
    return new Date(d.setDate(d.getDate() + offset));
}    

document.write(getTomorrow('16-02-2012',20) + ' test');

var k = getTomorrow('16-02-2012',1);
var myTime = k.getDate()+'-'+(k.getMonth()+1)+'-'+k.getFullYear();

alert(myTime);

JSFiddle Demo. See also http://www.w3schools./jsref/jsref_obj_date.asp.

 var d=new Date();                 

d.setTime((d.getTime() + 86400 * 1000*1)); 

document.write(d);

document.write(d.getDay()+"-"+parseInt(d.getMonth()+1)+"-"+d.getFullYear());

if you need to know the date of day after tommorow , just change 1000*1 to 1000*2.

i giving a example

var year = 2010, month = 9, day = 14;
    // The value of `meses`
    var offset = 1; // Tomorow

    var future_date = new Date(year, month , day+offset);

    console.log(future_date);