records = [
{
name: "Alpha",
set: 5,
weight: 185
},
{
name: "Alpha",
set: 5,
weight: 350
},
{
name: "Bravo",
set: 5,
weight: 185
},
{
name: "Charlie",
set: 5,
weight: 185
},
{
name: "Delta",
set: 5,
weight: 185
}
]
I have a JSON array of multiple records and I need to filter these records by name and weight. So for example, since there are two "Alpha" records, I need to only pull in the one with the highest weight (which would be the second record). I have no idea how to filter and rebuild this array with only the desired results.
I need to keep the original array intact as I'll be displaying ALL in a table, but I need to build a secondary array with only the objects with the greatest value, by name.
records = [
{
name: "Alpha",
set: 5,
weight: 185
},
{
name: "Alpha",
set: 5,
weight: 350
},
{
name: "Bravo",
set: 5,
weight: 185
},
{
name: "Charlie",
set: 5,
weight: 185
},
{
name: "Delta",
set: 5,
weight: 185
}
]
I have a JSON array of multiple records and I need to filter these records by name and weight. So for example, since there are two "Alpha" records, I need to only pull in the one with the highest weight (which would be the second record). I have no idea how to filter and rebuild this array with only the desired results.
I need to keep the original array intact as I'll be displaying ALL in a table, but I need to build a secondary array with only the objects with the greatest value, by name.
Share Improve this question asked Mar 21, 2017 at 4:54 Joe BerthelotJoe Berthelot 7354 gold badges17 silver badges33 bronze badges 1- Refer this similar Question : stackoverflow./a/17037756/6449750 – Hardik Vaghani Commented Mar 21, 2017 at 5:04
4 Answers
Reset to default 4You can use lodash 4+ for this.
var sortedArray = _.orderBy(records, ['weight'], ['desc']);
This will sort the array by weight. Then , _.uniqBy(sortedArray,'name')
This will return the final array.
var records = [
{
name: "Alpha",
set: 5,
weight: 185
},
{
name: "Alpha",
set: 5,
weight: 350
},
{
name: "Bravo",
set: 5,
weight: 185
},
{
name: "Charlie",
set: 5,
weight: 185
},
{
name: "Delta",
set: 5,
weight: 185
}
]
var sortedArray = _.orderBy(records, ['weight'], ['desc'])
_.uniqBy(sortedArray,'name')
I remend a functional programming approach:
var newRecords = records
.filter(function(record) {
return records.find(function(innerRecord) {
return innerRecord.name === record.name && innerRecord.weight > record.weight; }) === undefined;
});
In this example, you return only records where you cannot find a record sharing the same name but with a larger weight. Also, your newly re-built array is stored in newRecords
, leaving your original array intact.
I remend you start using lodash and dont spend time to create your own functions. For example, to sort your array by name you should write the following code:
var records = [
{
name: "Alpha",
set: 5,
weight: 185
},
{
name: "Alpha",
set: 5,
weight: 350
},
{
name: "Bravo",
set: 5,
weight: 185
},
{
name: "Charlie",
set: 5,
weight: 185
},
{
name: "Delta",
set: 5,
weight: 185
}
];
var sorted = _.sortBy(records, ['name']);
And second case, to filter by name and weight
var filtered = _.filter(records, [ 'name': 'Alpha', 'weight': 350 ]);
This first sorts the items in name order and weight order and then filter out all but the first of each item.
var records = [{
name: "Alpha",
set: 5,
weight: 185
},
{
name: "Alpha",
set: 5,
weight: 350
},
{
name: "Bravo",
set: 5,
weight: 185
},
{
name: "Charlie",
set: 5,
weight: 185
},
{
name: "Charlie",
set: 5,
weight: 200
},
{
name: "Delta",
set: 5,
weight: 185
}
]
console.log(
records.sort((a, b) => {
if (a.name === b.name) {
return a.weight >= b.weight ? -1 : 1
}
return a.name > b.name ? 1 : -1
})
.filter((rec, i, arr) => {
if (i === 0) return true
return rec.name !== arr[i - 1].name
})
)