This is not necessarily an issue, more a curiosity that came up via an ESLint error which led me to wonder if there was a better way that just disabling ESLint for this line.
Consider the code snippet below. ESLint will give an error if the react/destructuring-assignment rule is enabled, preferring
const { arrayToPrint } = myArrays to const arrayToPrint = myArrays[arrayName]
My question is, and I haven't been able to find any reference to this so I'm guessing not, is there a way to move [arrayName] to the lefthand side of the assignment to destructure without a reference to the actual object property?
const myArrays = {
arrayOne: ['one'],
arrayTwo: ['two'],
arrayThree: ['three'],
}
const arrayPrinter = function arrayPrinter(arrayName) {
const arrayToPrint = myArrays[arrayName]
return arrayToPrint
}
console.log(arrayPrinter('arrayTwo'))This is not necessarily an issue, more a curiosity that came up via an ESLint error which led me to wonder if there was a better way that just disabling ESLint for this line.
Consider the code snippet below. ESLint will give an error if the react/destructuring-assignment rule is enabled, preferring
const { arrayToPrint } = myArrays to const arrayToPrint = myArrays[arrayName]
My question is, and I haven't been able to find any reference to this so I'm guessing not, is there a way to move [arrayName] to the lefthand side of the assignment to destructure without a reference to the actual object property?
const myArrays = {
arrayOne: ['one'],
arrayTwo: ['two'],
arrayThree: ['three'],
}
const arrayPrinter = function arrayPrinter(arrayName) {
const arrayToPrint = myArrays[arrayName]
return arrayToPrint
}
console.log(arrayPrinter('arrayTwo'))-
For clarity, you can replace
function arrayPrinter(arrayName)byarrayName =>– Nino Filiu Commented Feb 20, 2019 at 23:13 -
1
What's wrong with
let { arrayTwo } = myArrays; let arrayToPrint = arrayTwo;? – Nino Filiu Commented Feb 20, 2019 at 23:15 - @NinoFiliu nothing wrong with that at all, and it's probably a better pattern if I refactor my code, but the question still stands ;) – Ben Commented Feb 20, 2019 at 23:19
- @NinoFiliu actually passing the array itself doesn't end up helping me. The use-case I have is updating the state of a parent ponent from a child, adding to one of several arrays based on a selection in the child ponent, so the child is telling the parent which value to add to which array (in parent state, and shared with other ponents). – Ben Commented Feb 20, 2019 at 23:30
- @Ben you can see this stackoverflow./questions/54605286/… – Code Maniac Commented Feb 21, 2019 at 8:19
2 Answers
Reset to default 11Destructuring can be done with puted property:
const { [arrayName]: arrayToPrint } = myArrays;
A simply way to do that is to use Object.entries(myArrays) .
/* example: expected output of console.log(Object.entries(myArrays)[1]) is ["arrayTwo": Array ["two"]]